Hello Users
Our qualexe service will not be available in between 11:30 pm to 4:00 am due to server maintenance activity
Gujarat Technological University (GTU), located in Gujarat, India, is a public state university with 486 affiliated colleges throughout the state. The university boasts a substantial enrollment of approximately 225,000 students, offering a diverse range of programs, including Diplomas, Undergraduate, and Postgraduate degrees, as well as a well-established Doctoral program.
Sr. No. | Events | Dates & Time |
---|---|---|
1 | Opening date of online registration | 27/01/2025, 1:00 PM |
2 | Closingdate of online registration | 30/3/2025, 12:00 Midnight |
3 | Admit card download | 10/4/2025 onwards |
4 | Exam Date | April 19, 2025 |
Rs. 250 per Candidate
The DDCET Rank will be available online, and the merit will be valid for the respective year only.
Program | Paper Number | Paper | No. of Question | Maximum Marks | Time Duration |
---|---|---|---|---|---|
Engineering and Technology | BE 01 | Basics of Science and Engineering | 50 | 100 | 150 Minutes |
BE 02 | Aptitutde Test (Mathematics and soft skill) | 50 | 100 | ||
Total | 100 | 200 |
Sr no | Topic | Sub-topic | Weightage (%) |
---|---|---|---|
1 | Units and Measurement | Physical quantities and units. Interconversion of units MKS (SI) to CGS and vice versa. Errors, Estimation of error, relative error, percentage error, propagation of errors. Measurement with Vernier caliper and micrometer screw gauge. |
12 |
2 | Classical Mechanics | Linear motion, velocity, acceleration, force, Newtons laws of motion, linear momentum and impulse of force. Circular motion, angular velocity, angular acceleration, centripetal and centrifugal force. Work, energy, kinetic energy, potential energy, power. |
12 |
3 | Electric Current |
|
12 |
4 | Heat and thermometry | Modes of heat transfer Various temperature scale, conversion of temperature, Kelvin Celsius, Kelvin Fahrenheit, Fahrenheit Celsius and vice versa. Heat capacity and specific heat. Thermal conductivity, coefficient of thermal conductivity, linear thermal expansion. |
12 |
5 | Wave motion, optics and acoustics | Types of waves, (progressive, stationary, mechanical, non-mechanical, transverse, longitudinal). Frequency, wavelength, periodic time and their relations. Properties and applications of electromagnetic waves (ordinary light, LASER) and sound waves (ultrasonic wave, audible wave). Amplitude, intensity, phase and wave equations. Reflection, refraction, Snells law, absolute refractive index, relative refractive index, total internal reflection, critical angle, optical fiber (construction, properties and applications). Reverberation, Reverberation time, Sabines formula, echo, absorption coefficient. |
12 |
6 | Chemical Reactions and Equations |
|
6 |
7 | Acids, Bases and Salts |
|
8 |
8 | Metals and Non-metals |
|
6 |
9 | Computer Practice |
|
10 |
10 | Environmental Sciences |
|
10 |
Sr. no | Topics | Sub-topics | Weightage(%) |
---|---|---|---|
1 | Determinant and Matrices |
Determinant and its value up to 3rd order (Without properties) Concept of a Matrix Types of Matrices (Rectangular matrix, Square matrix, Null matrix, Diagonal matrix, Scalar matrix, Identity matrix, Singular and Non-singular matrix) Addition, Subtraction and multiplication by scalar of matrices Product of two matrices Adjoint and Inverse of a matrix of order 2X2. Solution of Simultaneous linear equations of two variables |
8 |
2 | Trigonometry | Units of Angles (degree and radian) Trigonometric Functions Periods of Trigonometric functions Allied & Compound Angles, Multiple Submultiples angles Sum and factor formula |
6 |
3 | Vectors | Introduction of a Vector Direction and Magnitude Types of vectors (Null vector, Unit Vector) Addition, Subtraction. Scalar product (Dot product) and Vector Product (Cross product) Angle between two Vectors |
4 |
4 | Coordinate Geometry |
Introduction and slope of a line Equation of a line (Two-point form, Slope point form, Intercept form, General form) Condition of parallel and perpendicular lines Equation of Parallel and Perpendicular lines to the given line Angle between two lines Equation of a circle with centre and radius To find centre and radius from general equation of a circle |
4 |
5 | Function & Limit | Function and simple examples Limit of a Function Standard formulae of Limit and related simple examples |
6 |
6 | Differentiation and its Applications |
Concept of Differentiation Working rule: Sum, Subtraction, Product and Quotient Chain Rule Derivative of Implicit functions, Parametric functions Logarithmic Differentiation Successive Differentiation up to second order Applications: Velocity, Acceleration of given simple functions |
8 |
7 | Integration | Concept of Integration Working rules and Integral of standard functions Method of substitution & Integration by parts (simple examples) Definite Integral (simple examples) |
8 |
8 | Logarithm | Logarithm as a function Laws of Logarithm and related Simple examples |
4 |
9 | Statistics | Mean, Median and Mode for ungrouped data | 2 |
10 | Comprehension of Unseen Passage | An unseen passage will be given followed by 5 questions. Students have to read the passage and answer the questions. | 10 |
11 | Theory of Communication | Process of Communication Verbal and Non-verbal Communication Barriers to Communication |
10 |
12 | Techniques of Writing | Parts of Letter and Email Types of Business Letter (Inquiry, Reply, Order, Complaint, Adjustment) Common Abbreviations used in Business Letter |
10 |
13 | Grammar | Parts of Speech 1) Noun 2) Pronoun 3) Adjective 4) Adverb 5) Verb 6) Preposition 7) Connectors 8) Interjection Tenses Subject Verb Agreement |
10 |
14 | Correction of Incorrect Words and Sentences | Word Correction: Students have to choose correct spelling of the word from the options given Sentence Correction: Students have to choose grammatically or structurally correct sentence from the options given. |
10 |
Marking System:
1. What is DDCET, and how is it relevant to Gujarat Technological University (GTU)
DDCET stands for Diploma to Degree Common Entrance Test, a crucial examination at GTU facilitating the transition from diploma to degree programs in the various disciplines.
2. Can you provide an overview of GTU and its affiliation with DDCET
GTU, located in Gujarat, India, is a public state university with 486 affiliated colleges. DDCET serves as a bridge for students aspiring to shift from diploma courses to degree programs within the university.
3. What are the important dates for the DDCET application process
The online registration for DDCET typically opens in January 2025, and the exam is scheduled to take place on 19/04/2025.
4. How can I apply for the DDCET, and what is the application fee
The registration link for DDCET is mentioned below. Interested candidates can apply online through this link during the specified registration period. The nonrefundable application fee is Rs. 250 per candidate.
Registration link: www. gujacpc.admissions.nic.in
5. What is the selection process for DDCET, and how is merit determined
The DDCET Rank is available online, and the merit obtained in the exam is valid for the respective year only.
6. Could you provide details about the DDCET exam pattern
The DDCET exam consists of two papers: BE 01 (Basics of Science and Engineering) and BE 02 (Aptitude Test - Mathematics and soft skills). Each paper has 50 questions, with a total of 100 questions and 200 marks. The duration for the exam is 150 minutes.
7. How is the DDCET exam marked, and are there negative markings
Each correct answer in DDCET is awarded 2 marks, while each wrong answer incurs a 0.5 negative mark.
8. What additional support or resources are available for DDCET preparation
QUALEXE will offer well-designed test series and tournaments to facilitate quality exercise for DDCET candidates. candidates will be able to appear in DDCET like testseries for better practice and compare their performace with other candicates.
9. Is the DDCET merit valid for multiple years
No, the merit obtained in DDCET is valid for the respective year only.
10. How can I stay updated on any changes or announcements related to DDCET
For the latest and most accurate information, candidates are advised to regularly check the official GTU website and communications from the examination office. Additionally, all the latest updates about the DDCET Exam will be available on the QUALEXE website. So, keep visiting our website regularly for any announcements or changes.
Subject | Number of questions |
---|---|
POWER ELECTRONICS & DRIVES | 4 |
ELECTROMAGNETICS | 1 |
POWER SYSTEM | 8 |
BASIC ELECTRONICS | 4 |
SIGNALS & SYSTEMS | 4 |
ELECTRICAL MACHINES | 8 |
CONTROL SYSTEM ENGINEERING | 3 |
DIGITAL ELECTRONICS | 2 |
ELECTRICAL CIRCUIT ANALYSIS | 2 |
Total | 36 |
Correct Ans: C
Correct Ans: C
Correct Ans: B
Correct Ans: D
Correct Ans: C
Correct Ans: B
Correct Ans: A
Correct Ans: B
Correct Ans: C
Correct Ans: B
Correct Ans: C
Correct Ans: D
Correct Ans: A
Correct Ans: B
Correct Ans: B
Correct Ans: B
Correct Ans: C
Correct Ans: C
Correct Ans: C
Correct Ans: D
Correct Ans: B
Correct Ans: A
Correct Ans: D
Correct Ans: D
Correct Ans: A
Correct Ans: B
Correct Ans: A
Correct Ans: B
Correct Ans: A
Correct Ans: D
Correct Ans: A
Correct Ans: D
Correct Ans: C
Correct Ans: C
Correct Ans: C
Correct Ans: D
Subject | Number of questions |
---|---|
Basics of Science and Engineering (DDCET) | 50 |
Aptitude Test (Mathematics and Soft Skill) DDCET | 50 |
Total | 100 |
Correct Ans: D
Solution:
\(\Rightarrow\) When glass cools unevenly due to \(\textbf{small thermal conductivity}\), thermal stress develops, causing cracks. Mathematically, thermal stress \( \sigma = E \alpha \Delta T \), where \( E \) is Young's modulus, \( \alpha \) is thermal expansion coefficient, and \( \Delta T \) is temperature gradient.
Correct Ans: C
Solution:
\(\Rightarrow\) Boiling water maintains constant temperature (\( 100^\circ C \) at 1 atm) because heat energy (\( Q = mL \)) is used for phase change (latent heat of vaporization \( L \)), not increasing kinetic energy. Thus, \( \Delta T = 0 \).
Correct Ans: A
Solution:
\(\Rightarrow\) Convert \( 37^\circ C \) to Fahrenheit: \( T_F = \frac{9}{5}T_C + 32 = \frac{9}{5} \times 37 + 32 = 98.6^\circ F \).
Correct Ans: C
Solution:
\(\Rightarrow\) Thermal conductivity (\( k \)) measures heat transfer rate per unit area and temperature gradient. SI unit: \( \text{W/mK} \) (Watt per meter per Kelvin). Derived from Fourier's law: \( Q = -kA \frac{dT}{dx} \).
Correct Ans: B
Solution:
\(\Rightarrow\) Audible frequency range for humans: \( 20\ \text{Hz} \) (low-pitched) to \( 20\ \text{kHz} \) (high-pitched). Ultrasonic waves (\( >20\ \text{kHz} \)) and infrasonic waves (\( <20\ \text{Hz} \)) are inaudible.
Correct Ans: D
Solution:
\(\Rightarrow\) Speed of light in vacuum (\( c \)) is a fundamental constant: \( c = 299,792,458\ \text{m/s} \approx 3 \times 10^8\ \text{m/s} \).
Correct Ans: A
Solution:
\(\Rightarrow\) Period (\( T \)) and frequency (\( f \)) are inversely related: \( T = \frac{1}{f} = \frac{1}{20\ \text{Hz}} = 0.05\ \text{sec} \).
Correct Ans: D
Solution:
\(\Rightarrow\) LASER properties: \(\textbf{Unidirectional}\) - travels in one direction, \(\textbf{Focused}\) - narrow beam, \(\textbf{Coherent}\) in-phase waves, and \(\textbf{Stimulated}\) - emission. Hence, all options are correct.
Correct Ans: C
Solution:
\(\Rightarrow\) Reverberation time (\( T \)) is calculated using Sabine's formula: \( T = \frac{0.161V}{A} \), where \( V = 5000\ \text{m}^3 \) (volume) and \( A = 900\ \text{OWU} \) (absorption). Substituting: \( T = \frac{0.161 \times 5000}{900} = 0.894\ \text{sec} \).
Correct Ans: B
Solution:
\(\Rightarrow\) Numerical Aperture (\( NA \)) for optical fiber: \( NA = \sqrt{n_1^2 - n_2^2} \), where \( n_1 \) (core) and \( n_2 \) (cladding) are refractive indices. This determines light-gathering capacity.
Correct Ans: C
Solution:
\(\Rightarrow\) Here, a single element \(CaCO_{3}\) breaks down into two product that is \(CaO\) and \( CO_{2}\).
\(\Rightarrow\) Hence, this is a decomposition process.
Correct Ans: C
Solution:
\(\Rightarrow\) The formula of lead sulphate is:\(PbSO_4\)
where,
\(Pb = Lead\)
\(SO_4 = Sulphate \: ion\)
Correct Ans: B
Solution:
\(\Rightarrow\) The given chemical equation is
\(\quad \:Al + HCl \rightarrow AlCl_3 + H_2 \)
\(\Rightarrow\) Here, the number of atoms of hydrogen and chlorine is not equal on both the side.
\(\text {Step 1:}\) Balance \(Cl\) both side as it has maximum atoms.
\(\Rightarrow\) To do this multiply 3 with \(HCl\) on the reactant side
\(\implies Al + 3HCl \rightarrow AlCl_3 + H_2 \)
\(\text {Step 2:}\) Balance \(H\) both side.
\(\Rightarrow\) Reactant have 3 atoms and product have 2 atoms of \(H\), which can be balanced out as follow:
\(\implies Al + 2\times 3 HCl \rightarrow AlCl_3 + 3\times H_2 \)
\(\implies Al + 6HCl \rightarrow AlCl_3 + 3H_2 \)
\(\text {Step 3:}\) Now, we need to balance \(Cl\) again.
\(\Rightarrow\) Reactant have 6 atoms and product have 3 atoms of \(Cl\), which can be balanced out as follow:
\(\implies Al + 6HCl \rightarrow 2AlCl_3 + 3H_2 \)
\(\text {Step 4:}\) Finally, we need to balance \(Al\).
\(\Rightarrow\) Reactant have 1 atoms and product have 2 atoms of \(Al\), which can be balanced out as follow:
\(\implies 2Al + 6HCl \rightarrow 2AlCl_3 + 3H_2 \)
Correct Ans: C
Solution:
\(\Rightarrow\) Sodium zincate - \(Na_2ZnO_2\).
\(\Rightarrow\) It is formed when zinc reacts with sodium hydroxide \((NaOH)\) in an aqueous solution.
\(\Rightarrow\) It is often used in galvanizing and electroplating processes and can also be found in some types of batteries.
Correct Ans: B
Solution:
\(\Rightarrow\) Basic oxides are metal oxides that react with water to form a base or with acids to form a salt and water.
\(\Rightarrow\) They are typically ionic compounds formed by the reaction of metals with oxygen.
Correct Ans: B
Solution:
\(\Rightarrow\) Magnesium hydroxide \((Mg(OH)_2)\) - a milky white liquid is known as milk of magnesia.
Correct Ans: B
Solution:
\(\Rightarrow\) Bleaching powder is also known as calcium hypochlorite, and its formula is \(CaOCl_2\).
Correct Ans: A
Solution:
\(\Rightarrow\) lodine is non metal having lustrous appearance.
Correct Ans: D
Solution:
The correct answer is: Aluminium (Al)
\(\Rightarrow\) Among metals, aluminium does not react with cold or hot water due to the formation of a passive oxide layer \(Al_2 O_3\) on its surface. However, it does react with steam (water vapour) at high temperatures to form aluminium oxide and hydrogen gas:
\[
2Al + 3H_2O (g) \rightarrow Al_2O_3 + 3H_2 \uparrow
\]
Other metals comparison:
\(\rightarrow\) Sodium (Na) and Potassium (K): React vigorously with cold water.
\(\rightarrow\) Calcium (Ca) and Magnesium (Mg): React with cold or hot water.
\(\rightarrow\) Iron (Fe): Reacts slowly with steam.
\(\rightarrow\) Zinc (Zn): Also reacts with steam.
\(\therefore\) Aluminium fits the condition best — no reaction with cold or hot water, but reacts with steam
Correct Ans: A
Solution:
\(\Rightarrow\) The figure shows the list of elements arranged according to their reactivity.
Correct Ans: B
Solution:
\(\Rightarrow\) A single bit can only have two possible values: 0 or 1. Computers rely on these values to store and handle information.
\(\Rightarrow\) Bits are usually combined to create bigger units of data like bytes, which consist of 8 bits, or kilobytes, which contain 1024 bytes.
Correct Ans: D
Solution:
In MS Word, Pressing
\(\Rightarrow\) \(\text{Ctrl + End}\) moves the cursor to the end of the document .
\(\Rightarrow\) Only \(\text{Home}\) moves it to the beginning of the current line.
\(\Rightarrow\) \(\text{Ctrl +Up arrow} (\uparrow)\) jumps to the beginning of the current paragraph.
\(\Rightarrow\) \(\text{Ctrl + Home}\) returns to the very start of the document.
<a href="http://www.blog.com/index.html">
<a href="../index.html">
<a href="http://index.html">
Correct Ans: B
Solution:
\(\Rightarrow\) \(\text{Relative}\) URLs omit the scheme/host and specify a path relative to the current document (or its parent directories).
\(\Rightarrow\) \(\text{Absolute}\) URLs include a scheme (e.g. http:// or https://) and usually a host name.
Correct Ans: C
Solution:
The correct choice is \(\text{Both (A) and (B)}\).
\(\Rightarrow\) \(\text{=SUM(A2:D2)}\) uses a continuous range from A2 through D2.
\(\Rightarrow\) \(\text{=SUM(A2, B2, C2, D2)}\) explicitly lists each cell and add them up.
Correct Ans: A
Solution:
In MS Powerpoint,
\(\Rightarrow\) \(\text{Outline view}\) shows only the text content of your slides in a collapsible, linear outline on the left pane.
\(\Rightarrow\) \(\text{Notes page}\) displays a single slide at the top and its speaker notes below, formatted as a printable “notes page."
\(\Rightarrow\) \(\text{Reading view}\) runs your presentation in a window (not full‑screen) so you can step through slides as a viewer would.
\(\Rightarrow\) PowerPoint doesn’t include any option in view menu named \(\text{Tree View}\).
Correct Ans: B
Solution:
\(\Rightarrow\) Autotrophs are organisms capable of producing their own food, often through photosynthesis, using light energy, water, and carbon dioxide.
Correct Ans: C
Solution:
\(\Rightarrow\) A bag filter is an air pollution control device that uses fabric bags to trap particulate matter (dust and other small particles) from polluted gas streams.
\(\Rightarrow\) It's commonly used in industrial settings like boiler houses, factories, and power plants to reduce emissions and improve air quality.
Correct Ans: A
Solution:
\(\Rightarrow\) The process of producing energy by utilizing heat trapped inside the Earth's surface is called geothermal energy.
Correct Ans: D
Solution:
\(\Rightarrow\) A solar cell (also known as a photovoltaic cell) is a device that converts solar energy directly into electricity.
Correct Ans: C
Solution:
\(\Rightarrow\) The Paris Agreement aims to keep the increase in global temperature well below 2 degrees Celsius.
Correct Ans: B
Solution:
\(\Rightarrow\) Significant digits in 2025: All non-zero digits (2, 0, 2, 5) are significant. Zero (0) between non-zero digits is also significant.
Correct Ans: A
Solution:
\(\Rightarrow\) Zero error is \(\textbf{systematic}\) because it arises from instrument calibration (e.g., micrometer screw gauge not starting at zero) and is repeatable. Random errors vary unpredictably.
Correct Ans: C
Solution:
\(\Rightarrow\) Energy unit conversion: \( 1\ \text{J} = 10^7\ \text{erg} \).
Derived from \( 1\ \text{J} = 1\ \text{kg m}^2/\text{s}^2 \) and \( 1\ \text{erg} = 1\ \text{g cm}^2/\text{s}^2 \).
Correct Ans: D
Solution:
\(\Rightarrow\) Density of water in CGS: \( \rho = 1\ \text{g/cm}^3 \) (at \( 4^\circ C \)). In SI: \( 1000\ \text{kg/m}^3 \).
Correct Ans: A
Solution:
\(\Rightarrow\) For a sphere (\( V = \frac{4}{3}\pi r^3 \)), \% error in density (\( s \)): \( \Delta s\% = \Delta m\% + 3 \times \Delta r\% = 0.3\% + 3 \times 0.5\% = 1.8\% \).
Correct Ans: C
Solution:
\(\Rightarrow\) Least Count = \( \frac{\text{Pitch}}{\text{Divisions}} = \frac{1\ \text{mm}}{100} = 0.01\ \text{mm} \). Ensures precision in micrometer measurements.
Correct Ans: B
Solution:
\(\Rightarrow\) Linear momentum: \( p = mv \). SI unit: \( \text{kg m/s} \).
Correct Ans: D
Solution:
\(\Rightarrow\) Centripetal force (\( F_c = \frac{mv^2}{r} \)) always points \(\textbf{towards the centre}\) of circular motion, perpendicular to velocity.
Correct Ans: C
Solution:
\(\Rightarrow\) Newton's First Law: If net force \( F = 0 \), acceleration \( a = 0 \) (object remains at rest or moves uniformly).
Correct Ans: A
Solution:
\(\Rightarrow\) Angular velocity (\( \omega \)) for circular motion: \( \omega = \frac{v}{r} \) (radians/second).
Correct Ans: B
Solution:
\(\Rightarrow\) Force (\( F \)) via Newton's Second Law:
\( F = ma = 10\ \text{kg} \times 9.8\ \text{m/s}^2 = 98\ \text{N} \).
Correct Ans: C
Solution:
\(\Rightarrow\) Centripetal acceleration (\( a_c \)): \( a_c = \frac{v^2}{r} = \frac{(60\ \text{m/s})^2}{2\ \text{m}} = 1800\ \text{m/s}^2 \).
Correct Ans: D
Solution:
\(\Rightarrow\) Electric flux (\( \Phi \)) SI unit: \( \text{Nm}^2/\text{C} \).
From Gauss's law: \( \Phi = \oint \mathbf{E} \cdot d\mathbf{A} \).
Correct Ans: A
Solution:
\(\Rightarrow\) Electric field lines are \(\textbf{imaginary}\) curves representing the direction of the electric field (\( \mathbf{E} \)) at each point.
Correct Ans: B
Solution:
\(\Rightarrow\) Number of electrons in 1 Coulomb: \( n = \frac{Q}{e} = \frac{1\ \text{C}}{1.6 \times 10^{-19}\ \text{C}} = 6.25 \times 10^{18} \).
Correct Ans: A
Solution:
\(\Rightarrow\) Capacitance (\( C \)) with dielectric: \( C = \kappa C_0 \), where \( \kappa \) (dielectric constant) \( >1 \). Thus, \( C \) \(\textbf{increases}\).
Correct Ans: C
Solution:
\(\Rightarrow\) Coulomb's Law: \( F \propto \frac{1}{r^2} \). If distance \( r \) doubles, force reduces to \( \frac{1}{4} \).
Correct Ans: B
Solution:
\(\Rightarrow\) Series resistance: \( R_{\text{total}} = R_1 + R_2 + R_3 = 5\ \Omega + 10\ \Omega + 15\ \Omega = 30\ \Omega \).
Correct Ans: A
Solution:
\(\Rightarrow\) Specific heat capacity (\( c \)): Heat required per unit mass to raise temperature by \( 1^\circ C \). SI unit: \( \text{J/kg K} \).
Correct Ans: B
Solution:
\(\Rightarrow\) Energy conversion: \( 1\ \text{kcal} = 4186\ \text{J} \) (exact: \( 1\ \text{cal} = 4.186\ \text{J} \)).
Correct Ans: C
Solution:
\[
(x + 3)^2 + y^2 - 2 = 0
\]
\[
(x + 3)^2 + y^2 = 2
\]
Standard form:
\[
(x - h)^2 + (y - k)^2 = r^2
\]
Where:
- \((h, k)\) is the centre of the circle
- \(r\) is the radius
Compare:
\[
(x + 3)^2 + y^2 = (x - (-3))^2 + (y - 0)^2
\]
\(\therefore h = -3 \: \& \: k = 0\)
\(\therefore\) The centre of the circle is \((-3, 0)\).
Correct Ans: B
Solution:
\[
f(x) = e^{\log x}
\]
\[where, \quad
e^{\log_e x} = x \quad \text{(for } x > 0 \text{ and natural log)}
\]
\[\therefore
f(x) = x
\]
\[\therefore
f(1) = 1
\]
Correct Ans: C
Solution:
\[
\lim_{x \to 0} \frac{\sin 2x}{\tan x}
\]
\[
\sin 2x = 2 \sin x \cos x
\quad \text{and} \quad
\tan x = \frac{\sin x}{\cos x}
\]
\[
\frac{2 \sin x \cos x}{\frac{\sin x}{\cos x}} = 2 \sin x \cos x \cdot \frac{\cos x}{\sin x}
\]
\[
= 2 \cancel{\sin x} \cos x \cdot \frac{\cos x}{\cancel{\sin x}} = 2 \cos^2 x
\]
Take the limit as \(x \to 0\)
\[
2 \cos^2 x = 2 \cdot 1 = 2
\]
Correct Ans: D
Solution:
\[
\lim_{n \to \infty} \left(1+\frac{5}{2n}\right)^{8n}
\]
\(\rightarrow\) Standard exponential limit identity:
\[
\lim_{n \to \infty} \left(1 + \frac{k}{n}\right)^n = e^k
\]
\(\rightarrow\) Rewrite the expression:
\[
\left(1 + \frac{5}{2n}\right)^{8n}
= \left[\left(1 + \frac{5}{2n}\right)^{2n}\right]^4
\]
\[
\left(1 + \frac{5}{2n}\right)^{2n} \to e^5 \quad \text{as } n \to \infty
\]
\[\therefore
\left[\left(1 + \frac{5}{2n}\right)^{2n}\right]^4 \to (e^5)^4 = e^{20}
\]
Correct Ans: A
Solution:
\[
\frac{d}{dx}\left(\log 5 + \sin \frac{\pi}{3}\right)
\]
\(\rightarrow\) \(\log 5\) is a constant (natural log of 5)
\(\rightarrow\) \(\sin \frac{\pi}{3} = \frac{\sqrt{3}}{2}\), also a constant
\(\therefore\) Derivative of a constant is 0
\[
\frac{d}{dx}(\text{constant}) = 0
\]
Correct Ans: C
Solution:
\[
\frac{d}{dx}(x^e + e^x - e^e)
\]
Differentiate each term:
1. \(\frac{d}{dx}(x^e) = e x^{e-1}\)
(Since \(e\) is a constant exponent)
2. \(\frac{d}{dx}(e^x) = e^x\)
3. \(\frac{d}{dx}(e^e) = 0\)
(Because it is a constant)
\[
\frac{d}{dx}(x^e + e^x - e^e) = e x^{e-1} + e^x
\]
Correct Ans: A
Solution:
\[
\frac{d}{dx} \log (\sin x)
\]
\(\rightarrow\) Apply the chain rule:
The derivative of \(\log(u)\) with respect to \(x\) is:
\[
\frac{d}{dx} \log(u) = \frac{1}{u} \cdot \frac{du}{dx}
\]
Here, \(u = \sin x\).
\[
\frac{d}{dx} \sin x = \cos x
\]
\[
\frac{d}{dx} \log (\sin x) = \frac{1}{\sin x} \cdot \cos x
\]
\[
\frac{\cos x}{\sin x} = \cot x
\]
Correct Ans: D
Solution:
\[
x + y = -2
\]
\(\Rightarrow\) Differentiate both sides:
\[\rightarrow
\frac{d}{dx}(x + y) = \frac{d}{dx}(x) + \frac{d}{dx}(y) = 1 + \frac{dy}{dx}
\]
\[\rightarrow
\frac{d}{dx}(-2) = 0
\]
\[\therefore
1 + \frac{dy}{dx} = 0
\]
Correct Ans: B
Solution:
\[
\int \frac{1}{e^x} \, dx
\]
\[where, \:\:
\frac{1}{e^x} = e^{-x}
\]
\[
\int e^{-x} \, dx
\]
\(\rightarrow\) The integral of \(e^{ax}\) with respect to \(x\) is \(\frac{e^{ax}}{a}\), where \(a\) is a constant. Here, \(a = -1\).
\[\therefore
\int e^{-x} \, dx = \frac{e^{-x}}{-1} = -e^{-x}
\]
\[\therefore
\int \frac{1}{e^x} \, dx = -e^{-x} + C
\]
Correct Ans: D
Solution:
\[
\int \frac{3}{5x^4} \, dx
\]
\[
\int \frac{3}{5} x^{-4} \, dx = \frac{3}{5} \int x^{-4} \, dx
\]
Use the power rule
\[
\int x^n \, dx = \frac{x^{n+1}}{n+1} \quad \text{for } n \neq -1
\]
Here, \(n = -4\), so:
\[
\int x^{-4} \, dx = \frac{x^{-3}}{-3} = -\frac{1}{3x^3}
\]
\[\therefore
\frac{3}{5} \cdot \left(-\frac{1}{3x^3}\right) = -\frac{1}{5x^3}
\]
Correct Ans: B
Solution:
\[
\int \frac{4x - 10}{x^2 - 5x + 1} \, dx
\]
Let:
\[
u = x^2 - 5x + 1 \Rightarrow du = (2x - 5)\,dx
\]
\[\therefore
\frac{4x - 10}{x^2 - 5x + 1} \, dx = \frac{2(2x - 5)}{u} \, dx = 2 \cdot \frac{du}{u}
\]
\[
\int 2 \cdot \frac{1}{u} \, du = 2 \ln |u| + C
\]
Substitute back: \(u = x^2 - 5x + 1\):
\[=
2 \ln |x^2 - 5x + 1| + C
\]
Correct Ans: A
Solution:
\[
\int_{-\pi}^{\pi} x^2 \sin x \, dx
\]
\(\rightarrow x^2\) is even: \(x^2 = (-x)^2\)
\(\rightarrow \sin x\) is odd: \(\sin(-x) = -\sin x\)
\[\therefore
x^2 \sin x \text{ is the product of even and odd functions ⇒ an odd function}
\]
\(\rightarrow\) Use symmetry of definite integrals.
\(\rightarrow\) The integral of an odd function over a symmetric interval \([ -a, a ]\) is always zero:
\[
\int_{-a}^{a} \text{(odd function)} \, dx = 0
\]
Correct Ans: D
Solution:
\[
\frac{\log 125}{\log 5}
\]
\[where, \:
\log 125 = \log (5^3) = 3 \log 5
\]
\[
\frac{\log 125}{\log 5} = \frac{3 \log 5}{\log 5}
\]
\[
= 3
\]
Correct Ans: C
Solution:
\[
\log 2 + 2 \log 3
\]
\[where, \:
2 \log 3 = \log (3^2) = \log 9
\]
\[\therefore
\log 2 + \log 9 = \log (2 \cdot 9) = \log 18
\]
Correct Ans: D
Solution:
The first five negative integers are:
\[
-1,\ -2,\ -3,\ -4,\ -5
\]
\[\therefore
\text{Mean} =\frac{sum}{number \: of \: terms}= \frac{-15}{5} = -3
\]
Correct Ans: C
Solution:
\[
\begin{bmatrix}
\tan x & -\csc x \\
-\sin x & -\cot x
\end{bmatrix}
\]
\[\therefore
\det = (\tan x)(-\cot x) - (-\csc x)(-\sin x)
\]
\[\therefore
\det = \left( \frac{\sin x}{\cos x} \right) \left( -\frac{\cos x}{\sin x} \right) - \left( -\frac{1}{\sin x} \right)(-\sin x)
\]
\[\therefore
\det = -1 - 1 = -2
\]
Correct Ans: B
Solution:
\[Given:
A = \begin{bmatrix}
3 & 1 & -2 \\
1 & 0 & 5 \\
-2 & 5 & 4
\end{bmatrix}
\]
\(\quad 1.\) Symmetric Matrix:
A matrix is symmetric if \( A = A^T \) (transpose equals the original).
\[
A^T = \begin{bmatrix}
3 & 1 & -2 \\
1 & 0 & 5 \\
-2 & 5 & 4
\end{bmatrix}
= A
\]
\(\therefore\) A is symmetric.
\(\quad 2.\) Skew-symmetric Matrix:
For a matrix to be **skew-symmetric**, \( A^T = -A \).
Here, since \( A = A^T \), it is **not** skew-symmetric.
\(\quad 3.\) Diagonal Matrix:
A diagonal matrix has non-zero entries only on the main diagonal and zeros elsewhere.
This matrix has non-zero off-diagonal elements (like 1 and -2), so it's not diagonal.
\(\quad 4.\) Singular Matrix:
A matrix is singular if its determinant is 0.
\[
\text{det}(A) =
3 \begin{vmatrix} 0 & 5 \\ 5 & 4 \end{vmatrix}
- 1 \begin{vmatrix} 1 & 5 \\ -2 & 4 \end{vmatrix}
+ (-2) \begin{vmatrix} 1 & 0 \\ -2 & 5 \end{vmatrix}
\]
\[
\text{det}(A) = -75 - 14 - 10 = -99 \neq 0
\]
\(\therefore\) It is not singular.
Correct Ans: C
Solution:
\[
A = \begin{bmatrix} 3 & 1 & 2 \end{bmatrix}, \quad B = \begin{bmatrix} -5 \\ 0 \\ 4 \end{bmatrix}
\]
\(\rightarrow\) \(A\) is a 1×3 row matrix, and \(B\) is a 3×1 column matrix,
\(\therefore\) The product \(AB\) is defined and will result in a 1×1 matrix.
\[\therefore
AB = (3)(-5) + (1)(0) + (2)(4)
= -15 + 0 + 8 = -7
\]
Correct Ans: D
Solution:
\[
A = \begin{bmatrix} 4 & 5 \\ -2 & -3 \end{bmatrix}
\]
\[\implies
A^{-1} = \frac{1}{\det(A)} \begin{bmatrix} d & -b \\ -c & a \end{bmatrix}
\quad \text{for} \quad A = \begin{bmatrix} a & b \\ c & d \end{bmatrix}
\]
\[\therefore
\det(A) = ad - bc = (4)(-3) - (5)(-2) = -12 + 10 = -2
\]
\[\therefore
A^{-1} = \frac{1}{-2} \begin{bmatrix} -3 & -5 \\ 2 & 4 \end{bmatrix}
= \begin{bmatrix} \frac{3}{2} & \frac{5}{2} \\ -1 & -2 \end{bmatrix}
\]
Correct Ans: B
Solution:
\[
\text{Radians} = \text{Degrees} \times \frac{\pi}{180}
\]
\[\implies
225^\circ = 225 \times \frac{\pi}{180} = \frac{225\pi}{180}=\frac{5\pi}{4}
\]
Correct Ans: B
Solution:
\[
\sin \theta = \frac{2}{\sqrt{5}}
\]
\[where, \:
\sin^2 \theta + \cos^2 \theta = 1
\]
\[\therefore
\left( \frac{2}{\sqrt{5}} \right)^2 + \cos^2 \theta = 1\] \[\Rightarrow \frac{4}{5} + \cos^2 \theta = 1
\Rightarrow \cos^2 \theta = 1 - \frac{4}{5} = \frac{1}{5}
\Rightarrow \cos \theta = \pm \frac{1}{\sqrt{5}}
\]
\[\therefore
\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{\pm \frac{1}{\sqrt{5}}}{\frac{2}{\sqrt{5}}} = \pm \frac{1}{2}
\]
Correct Ans: C
Solution:
\[Given:
\cos(3 + 4x)
\]
\[
\text{Period} = \frac{2\pi}{|B|}
\quad \text{for} \quad \cos(Bx + C)
\]
\(\rightarrow\) The function is in the form \(\cos(Bx + C)\), with:
\(\rightarrow\) \(B = 4\)
\(\rightarrow\) \(C = 3\)
\[
\text{Period} = \frac{2\pi}{|4|} = \frac{2\pi}{4} = \frac{\pi}{2}
\]
Correct Ans: A
Solution:
\[
\vec{A} = \hat{i} - 2\hat{j} - 2\hat{k}
\]
\[
|\vec{A}| = \sqrt{a^2 + b^2 + c^2}
\]
\[
|\vec{A}| = \sqrt{1^2 + (-2)^2 + (-2)^2}
= \sqrt{1 + 4 + 4}
= \sqrt{9}
= 3
\]
Correct Ans: D
Solution:
\[Given:
(\hat{i} \times \hat{j}) \circ \hat{k}
\]
Cross product:
\[
\hat{i} \times \hat{j} = \hat{k}
\]
Dot product:
\[
\hat{k} \cdot \hat{k} = 1
\]
\[
(\hat{i} \times \hat{j}) \circ \hat{k} = 1
\]
Correct Ans: C
Solution:
Given:
1. \(x - 2y = 3\)
2. \(3y + px - 1 = 0\)
\[
x - 2y = 3 \Rightarrow -2y = -x + 3 \Rightarrow y = \frac{1}{2}x - \frac{3}{2}
\]
\(\therefore\) slope \(m_1 = \frac{1}{2}\)
Line 2:
\[
3y + px = 1 \Rightarrow 3y = -px + 1 \Rightarrow y = \frac{-p}{3}x + \frac{1}{3}
\]
\(\therefore\) slope \(m_2 = \frac{-p}{3}\)
\(\Rightarrow\) The condition for perpendicular lines:
\[
m_1 \cdot m_2 = -1
\]
\[
\frac{1}{2} \cdot \left( \frac{-p}{3} \right) = -1
\Rightarrow \frac{-p}{6} = -1
\Rightarrow p = 6
\]
Correct Ans: D
Solution:
\(\Rightarrow\) A letter of adjustment is written in response to a \(\textbf{complaint letter}\) to address grievances or resolve issues.
Correct Ans: B
Solution:
\(\Rightarrow\) A letter of inquiry (B) seeks details about products/services, distinct from complaints or offers.
Correct Ans: C
Solution:
\(\Rightarrow\) The \(\textbf{inside address}\) (recipient's address) is essential in business letters for formal communication.
Correct Ans: C
Solution:
\(\Rightarrow\) The \(\textbf{complimentary close}\) (e.g., "Sincerely") is the courteous farewell in a letter.
Correct Ans: D
Solution:
\(\Rightarrow\) "PS" stands for \(\textbf{Post Script}\), used to add information after the main message.
Correct Ans: B
Solution:
\(\Rightarrow\) The adverb \(\textbf{quickly}\) modifies the verb "danced," describing how the action was performed.
Correct Ans: A
Solution:
\(\Rightarrow\) With "captain along with," the singular verb \(\textbf{has}\) agrees with the subject "captain."
Correct Ans: D
Solution:
\(\Rightarrow\) "None" with plural "products" requires plural verb \(\textbf{were}\) in past tense.
Correct Ans: B
Solution:
\(\Rightarrow\) The church is located \(\textbf{on}\) the lake's edge (surface contact), not above/over.
Correct Ans: A
Solution:
\(\Rightarrow\) Present simple tense \(\textbf{goes}\) indicates habitual action ("every morning").
Correct Ans: C
Solution:
\(\Rightarrow\) Correct spelling: \(\textbf{Fahrenheit}\), named after physicist Daniel Fahrenheit.
Correct Ans: A
Solution:
\(\Rightarrow\) Correct spelling: \(\textbf{Inconvenience}\) (meaning "trouble" or "hardship").
Correct Ans: D
Solution:
\(\Rightarrow\) Active voice correct: \(\textbf{"The police arrested the criminals"}\). Others are passive/grammatically incorrect.
Correct Ans: B
Solution:
\(\Rightarrow\) Present perfect continuous \(\textbf{"has been working"}\) shows ongoing action from past to present.
Correct Ans: A
Solution:
\(\Rightarrow\) Correct phrasing: \(\textbf{"vividly illustrated children's dictionary"}\) (proper adjective-noun order).
Correct Ans: C
Solution:
\(\Rightarrow\) Steps allow \(\textbf{access to water}\) in the stepwell, as described in the passage.
Correct Ans: B
Solution:
\(\Rightarrow\) "Cool shadowed walls" provide \(\textbf{relief from desert heat}\), contrasting the "scorching sun."
Correct Ans: D
Solution:
\(\Rightarrow\) Legends mention a \(\textbf{chamber of desert spirits}\) guarding secrets.
Correct Ans: A
Solution:
\(\Rightarrow\) "Forgotten dream" implies \(\textbf{historical significance and obscurity}\), not modern use.
Correct Ans: C
Solution:
\(\Rightarrow\) The scholar studies carvings for \(\textbf{clues to the stepwell's origin}\).
Correct Ans: A
Solution:
\(\Rightarrow\) \(\textbf{Decoding}\) is interpreting the sender's message by the receiver.
Correct Ans: D
Solution:
\(\Rightarrow\) \(\textbf{Kinesics}\) studies body language (gestures, expressions).
Correct Ans: B
Solution:
\(\Rightarrow\) \(\textbf{Shaking hands}\) is non-verbal; others involve spoken/written words.
Correct Ans: C
Solution:
\(\Rightarrow\) Socio-cultural barriers often cause \(\textbf{misinterpretation}\) due to differing norms.
Correct Ans: B
Solution:
\(\Rightarrow\) Emotions like anxiety create \(\textbf{psychological barriers}\) to effective communication.
Subject | Number of questions |
---|---|
Basics of Science and Engineering (DDCET) | 50 |
Aptitude Test (Mathematics and Soft Skill) DDCET | 50 |
Total | 100 |
Correct Ans: C
Correct Ans: B
Correct Ans: C
Correct Ans: D
Correct Ans: A
Correct Ans: B
Correct Ans: B
Correct Ans: B
Correct Ans: C
Correct Ans: A
Correct Ans: C
Correct Ans: A
Correct Ans: B
Correct Ans: A
Correct Ans: D
Correct Ans: D
Correct Ans: B
Correct Ans: C
Correct Ans: B
Correct Ans: C
Correct Ans: C
Correct Ans: D
Correct Ans: B
Correct Ans: The correct answer does not align perfectly with the provided options
Correct Ans: The correct answer does not align perfectly with the provided options
Correct Ans: A
Correct Ans: C
Correct Ans: B
Correct Ans: C
Correct Ans: C
Correct Ans: D
Correct Ans: A
Correct Ans: B
Correct Ans: D
Correct Ans: D
Correct Ans: C
Correct Ans: D
Correct Ans: B
Correct Ans: A
Correct Ans: C
Correct Ans: D
Correct Ans: The correct answer does not align perfectly with the provided options
Correct Ans: A
Correct Ans: B
Correct Ans: A
Correct Ans: B
Correct Ans: D
Correct Ans: C
Correct Ans: A
Correct Ans: B
Correct Ans: D
Correct Ans: B
Correct Ans: A
Correct Ans: B
Correct Ans: D
Correct Ans: A
Correct Ans: A
Correct Ans: C
Correct Ans: B
Correct Ans: D
Correct Ans: A
Correct Ans: C
Correct Ans: D
Correct Ans: B
Correct Ans: B
Correct Ans: D
Correct Ans: A
Correct Ans: D
Correct Ans: A
Correct Ans: C
Correct Ans: D
Correct Ans: B
Correct Ans: A
Correct Ans: D
Correct Ans: C
Correct Ans: A
Correct Ans: A
Correct Ans: B
Correct Ans: C
Correct Ans: A
Correct Ans: B
Correct Ans: B
Correct Ans: B
Correct Ans: A
Correct Ans: B
Correct Ans: B
Correct Ans: B
Correct Ans: D
Correct Ans: A
Correct Ans: C
Correct Ans: B
Correct Ans: C
Correct Ans: B
Correct Ans: B
Correct Ans: C
Correct Ans: A
Correct Ans: A
Correct Ans: D
Correct Ans: A
Correct Ans: D
Hello Users
Our qualexe service will not be available in between 11:30 pm to 4:00 am due to server maintenance activity
© 2022 Qualexe. All Rights Reserved