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Subject | Number of questions |
---|---|

POWER SYSTEM | 45 |

ELECTRICAL MACHINES | 22 |

ELECTRICAL ENERGY CONSERVATION AND AUDITING | 15 |

BASICS OF COMPUTER | 8 |

ELECTRICAL CIRCUIT ANALYSIS | 8 |

MEASUREMENT & INSTRUMENTATION | 2 |

Total | 100 |

- Load factor = Average load for a period / Peak load for the same period
- Load factor = Average load for a period x Peak load for the same period
- Load factor = Average load for a period + Peak load for the same period
- All of the above

**Correct Ans: A**

- Through cooling coil
- Through air
- By the flux
- None of the above

**Correct Ans: C**

- 100%
- 98%
- 50%
- 25%

**Correct Ans: B**

- 800 kWh
- 0.8 kWh
- 8 kWh
- None of the above

**Correct Ans: A & B**

- Electric line
- Transmission line
- All of the above
- None of the above

**Correct Ans: A**

- \(SO_2\)
- \(NO_x\)
- CO
- All of the above

**Correct Ans: D**

- 1 m
- 2 m
- 4m
- 8m

**Correct Ans: D**

- Thermocouple
- Pyrometer
- Resistance thermometer
- Thermometer

**Correct Ans: C**

- 11 kV
- 33 kV
- 66 kV
- 132 kV

**Correct Ans: B**

- Current
- Voltage
- Impedance
- all of above

**Correct Ans: D**

- 30 Volts
- 480 Volts
- 120 Volts
- 60 Volts

**Correct Ans: A**

- BERC
- GERC
- CSERC
- DGVCL

**Correct Ans: D**

- Ahmedabad
- Valsad
- Vadodara
- Godhra

**Correct Ans: C**

- Diversity factor =1 / Coincidence Factor
- Diversity factor =1 x Coincidence Factor
- Diversity factor =1 - Coincidence Factor
- All of the above

**Correct Ans: A**

- Expansion Board
- External Drive
- Mother Board
- All of above

**Correct Ans: C**

- Electric power system
- Electric power
- All of the above
- None of the above

**Correct Ans: A**

- Arithmetic logic unit, Mouse
- Arithmetic logic unit, Control unit
- Arithmetic logic unit, Integrated Circuits
- Control Unit, Monitor

**Correct Ans: B**

- Eddy Current and Hysteresis losses will be excessive
- Current will be too much high
- Transformer may start to smoke and burn
- No effect

**Correct Ans: A**

- \(700 W/m^2\)
- \(800 W/m^2\)
- \(1 kW/m^2\)
- \(2 kW/m^2\)

**Correct Ans: C**

- Regulating tariffs for generation and inter-state transmission of energy including tariffs
- Advising the government on tariff policy and promoting competition
- Efficiency and economy in the electricity industry
- All of the above

**Correct Ans: D**

- Measuring of safety voltage
- Protection of equipment from ground faults
- Discharging residual energies
- All of the above

**Correct Ans: C**

- Information
- Data
- Software programme
- System

**Correct Ans: A**

- All parts of India
- All parts of India except state of Jammu and Kashmir
- All the states of India
- In Gujarat only

**Correct Ans: B**

- Resistance.
- Capacitance.
- Inductance.
- Impedance.

**Correct Ans: B**

- 10 times longer
- 100 times longer
- Same time
- None of the above

**Correct Ans: A**

- Rewireable fuse
- Isolator
- Oil Circuit breaker
- Air break circuit breaker

**Correct Ans: A**

- One-phase
- Two-phase
- Three-phase
- None of the above

**Correct Ans: C**

- Transformer will operate with low efficiency
- Transformer will operate with high efficiency
- No effect
- Transformer may start to smoke and burn

**Correct Ans: D**

- 0.003 sec
- 0.001 sec
- 0.01 sec
- 0.1 sec

**Correct Ans: A**

- High cost of station and distribution equipment
- Poor voltage regulation
- High energy loss in conductor
- All of the above

**Correct Ans: D**

- Transmission Company
- Distribution Company
- Regulatory Commission
- Power Generation Company

**Correct Ans: D**

- Is yellow in colour
- Is lighter than air
- Is nontoxic
- Has pungent smell

**Correct Ans: C**

- \(P = V \times I\)
- \(P = I^2 \times R\)
- \(P = V^2/ R\)
- All of the above

**Correct Ans: D**

- 1 Farad
- 0.1 Farad
- 0.01 Farad
- 0.01 microF

**Correct Ans: C**

- Input unit
- Secondary storage unit
- Output Unit
- Primary Memory Unit

**Correct Ans: B**

- Reduced requirement of oil
- Reduced requirement of air
- All of the above
- None of the above

**Correct Ans: A**

- No load
- Short circuit
- Full load
- None of the above

**Correct Ans: A**

- Primary winding and secondary winding
- Primary winding and Auxiliary winding
- Auxiliary winding and secondary winding
- None of the above

**Correct Ans: A**

- mechanical
- chemical
- heat
- Sound

**Correct Ans: B**

- Task bar
- Menu bar
- Desk top
- Control panel

**Correct Ans: D**

- Impedance relay
- Electromagnetic attraction type
- thermal relay
- Buchholz's relay

**Correct Ans: C**

- 2 June 2003
- 3 June 2003
- 2 May 2003
- None of the above

**Correct Ans: A**

- electrical charge
- electric current
- voltage
- All of the above

**Correct Ans: A**

- 1 H
- 0.1 H
- 1 mH
- 0.1 mH

**Correct Ans: C**

- Joule

- Newton
- Coulomb
- Henry

**Correct Ans: A**

- Over load
- Short circuit
- Over current
- All of the above

**Correct Ans: D**

- 3 to 8
- 10 to 18
- 20 to 30
- 40 to 50

**Correct Ans: A**

- ampere hours
- kWh
- amperes
- ampere-volts

**Correct Ans: C**

- 0.1 kW
- 0.04 kW
- 0.01 kW
- None of the above

**Correct Ans: C**

- Northern
- Southern
- Central
- Western

**Correct Ans: A**

- 34.64 kVA
- 75 kVA
- 20 kVA
- None of the above

**Correct Ans: A**

- Gujarat Urja Vikas Nigam Limited
- Gujarat Urja Vikas Nikash Limited
- Gujarat Urja Vyapar Nigam Limited
- None of the above

**Correct Ans: A**

- 0 \(\%\)
- 5 \(\%\)
- 25 \(\%\)
- 50 \(\%\)

**Correct Ans: A**

- Reduce hysteresis loss
- Reduce eddy current losses
- Reduce copper losses
- Reduce all above losses

**Correct Ans: B**

- How voltage and high current
- High voltage and low current
- Low voltage and high current
- None of the above

**Correct Ans: C**

- \(\pm 0.1 \%\)
- \(\pm 1 \%\)
- \(\pm 10 \%\)
- \(\pm 25 \%\)

**Correct Ans: C**

- Changes DC to AC
- Changes AC to DC
- Steps up or down DC Voltages & Current
- Steps up or down AC Voltages & Current

**Correct Ans: D**

- Decrease the secondary current
- Increase the primary current
- Have no effect on the secondary current
- Increase the secondary current

**Correct Ans: A**

- At the receiving end
- At the sending end
- At the intermediate point
- Anywhere in the line

**Correct Ans: C**

- High voltage applications
- Low voltage applications
- All of the above
- None of the above

**Correct Ans: A**

- Cogeneration
- Power generation
- Captive Power Plant
- None of the above

**Correct Ans: A**

- Power frequencies
- Higher frequencies entering generator or transformer units
- Either of above
- None of above

**Correct Ans: B**

- The consumers must readily understand the tariffs
- The tariff must be equitable amongst different consumers
- Tariffs can be modified from time to time
- All of the above

**Correct Ans: D**

- Stainless steel
- Hard pressed carbon
- porcelain
- copper tungsten alloy

**Correct Ans: D**

- Berry Type Transformer
- Core Type Transformer
- Shell Type Transformer
- None of the above

**Correct Ans: A**

- Tapi
- Vadodara
- Navsari
- Valsad

**Correct Ans: B**

- The computer is tired after working for the whole day.
- You are leaving for a very short time and want to resume your work shortly.
- When computer gets hanged frequently. Let it sleep for some time.
- You finish working and are going to bed.

**Correct Ans: B**

- Impedance
- Directional
- Non-directional
- None of the above

**Correct Ans: B**

- Electricity trader
- Electricity supplier
- All of the above
- None of the above

**Correct Ans: A**

- Power
- Current
- Voltage
- All of the above

**Correct Ans: A**

- 3.6 mega joules
- 2.6 mega joules
- 1.6 mega joules
- None of the above

**Correct Ans: A**

- Energy
- Current
- Voltage
- None of the above

**Correct Ans: A**

- Steps up the level of Voltage
- Steps down the level of current
- Step up the level of Frequency
- (a) and (b) only

**Correct Ans: D**

- Relays
- Transformer
- Electric Motor
- None of the above

**Correct Ans: A**

- It does not need an auxiliary breaking chamber
- Short break time of 2 to 2.5 cycles
- All of the above
- None of the above

**Correct Ans: C**

- Low specific resistance and high melting point
- Low specific resistance and low melting point
- High specific resistance and high melting point
- High specific resistance and low melting point

**Correct Ans: D**

- 11 kV
- 33 kV
- 60 kV
- 110 kV

**Correct Ans: B**

- The Parliament
- A State resolution
- All of the above
- None of the above

**Correct Ans: A**

- Uploading
- Retrieving
- Downloading
- All of the above

**Correct Ans: C**

- Phase Fault
- Over voltage Fault
- Earth Fault
- None of these

**Correct Ans: C**

- Use of tap changing transformers
- Switching in shunt capacitors at the receiving end during heavy loads
- Use of capacitors to neutralize the effect of series reactance
- Any of the above methods

**Correct Ans: D**

- Bulk oil type CB
- Air blast CB
- Vacuum CB
- Sulphur hexafluoride CB

**Correct Ans: D**

- 20%
- 40%
- 50%
- 30%

**Correct Ans: A**

- Regenerative cycle efficiency
- Rankine cycle efficiency
- Carnot cycle efficiency
- None of the above

**Correct Ans: D**

- Conservator
- Breather
- Buchholz Relay
- Exciter

**Correct Ans: D**

- Domestic
- Agricultural
- Industrial and Commercial
- All of the above

**Correct Ans: D**

- Current
- Voltage
- Frequency
- All of the above

**Correct Ans: C**

- Conversion flexibility from one voltage level to other
- AC can be easily converted into DC by using a rectifier
- AC is easy to maintain & can be easily distributed at long distances
- All of the above

**Correct Ans: D**

- The spring tension
- The rate of flux built up
- Armature core air gap
- All of the above

**Correct Ans: D**

- 5,000 K
- 8,000 K
- 10,000 K
- None of the above

**Correct Ans: A**

- Navigation program
- Switching between program
- Start a program
- All of above

**Correct Ans: D**

- Delta-Star
- Star-Delta
- Delta-Delta
- Star-Star

**Correct Ans: D**

- DERC
- MGVCL
- GERC
- CSERC

**Correct Ans: B**

- kVAR
- kW
- kVA
- Horse power

**Correct Ans: C**

- Mutual induction
- Mutual capacitance
- All of the above
- None of the above

**Correct Ans: A**

- Volts
- Amperes
- Ampere hour
- kW

**Correct Ans: D**

- Single - phase
- Three - phase
- Two-phase
- None of the above

**Correct Ans: B**

- GERC
- DGVCL
- GETCO
- MGVCL

**Correct Ans: C**

- Single magnetic circuit
- Double magnetic circuit
- All of the above
- None of the above

**Correct Ans: A**

- Both Step-Up and Step-Down transformer
- Step-Down Transformer
- Step-Up Transformer
- None of these

**Correct Ans: A**

Subject | Number of questions |
---|---|

ELECTRICAL CIRCUIT ANALYSIS | 12 |

ENGLISH | 10 |

POWER SYSTEM | 65 |

MEASUREMENT & INSTRUMENTATION | 1 |

ELECTRICAL ENGINEERING MATERIALS | 1 |

UTILIZATION OF ELECTRICAL ENERGY | 1 |

GENERAL KNOWLEDGE | 10 |

Total | 100 |

- \(ampere \times volt\)
- \((ampere)^2\times ohm\)
- \( ampere / volt \)
- \(joules / sec \)

**Correct Ans: C**

- active and unilateral
- active and bilateral
- passive and bilateral
- passive and unilateral

**Correct Ans: A**

- both linear and nonlinear circuits
- linear circuits only
- passive time invariant circuits
- nonlinear circuits only

**Correct Ans: A**

- nature of electrolyte and nature of electrode
- physical dimensions of a cell
- nature of electrolyte
- nature of electrode

**Correct Ans: A**

- current capacity
- life of the cells
- efficiency
- voltage rating

**Correct Ans: A**

- surge diverters
- earthing screens
- over head ground Wires
- none

**Correct Ans: A**

- both inductance and capacitance of the system
- the type of circuit breaker
- the inductance of the system only
- the capacitance of the system only

**Correct Ans: A**

- directly proportional to
- inversely proportional to
- independent of
- directly proportional to square of

**Correct Ans: A**

- capacitance
- resistance
- inductance
- all

**Correct Ans: A**

- \(\frac{V}{R}\)
- \(\frac{V}{X_C}\)
- \(\frac{V}{X_L}\)
- none

**Correct Ans: A**

- \(\frac{L}{CR}\)
- \(\frac{LC}{R}\)
- \(LCR\)
- \(\frac{C}{LR}\)

**Correct Ans: A**

- rms phase voltage
- rms line to line voltage
- Peak phase voltage
- Peak line to line voltage

**Correct Ans: B**

- capacitance very small
- capacitance calculation easy
- the connection elegant
- the power factor correction more effective

**Correct Ans: A**

- unity
- zero
- 0.5
- 0.866

**Correct Ans: A**

- unequal line voltage
- high voltage
- low voltage
- none

**Correct Ans: A**

- Intrinsic semiconductor
- Metal
- Insulator
- Alloy

**Correct Ans: B**

- 0.6
- 1.63
- 2.5
- 0.4

**Correct Ans: A**

- display devices and thermal sensors
- ultrasonic amplification and display devices
- thermal sensors and transducers
- transducers and ultrasonic amplification

**Correct Ans: A**

- amperes
- volts
- ampere-volts
- ampere hours

**Correct Ans: A**

- voltage rating
- current rating
- current rating and voltage rating
- none

**Correct Ans: A**

- It is highly inflammable
- It is electronegative in nature
- It has high dielectric strength
- It is non toxic

**Correct Ans: A**

- never inserted in neutral wire
- normally inserted in phase wire
- normally inserted in neutral wire
- never inserted in phase wire

**Correct Ans: B**

- parallel
- series
- series-parallel
- end-to-end

**Correct Ans: A**

- all
- stay wire
- structural components
- earth wire

**Correct Ans: A**

- Forebay
- Spill ways
- Penstock
- Reservoir

**Correct Ans: A**

- low temperature and pressure conditions
- higher temperature conditions
- less rejection of heat in the condenser
- higher pressure conditions

**Correct Ans: A**

- decreases
- increases
- remain the same
- may increase or decrease

**Correct Ans: A**

- 0.15
- 0.25
- 0.4
- 0.6

**Correct Ans: A**

- relieve water hammer pressure in the penstock pipe
- supply water at constant pressure
- produce surge in the pipeline
- none

**Correct Ans: A**

- both peak and off-peak load
- off peak load
- full load
- peak load

**Correct Ans: A**

- 5W
- 10 W
- 1W
- 20 W

**Correct Ans: C**

- penstock
- surge tank
- turbine casing
- draft tube

**Correct Ans: A**

- feed water pump
- superheater
- condenser
- turbine

**Correct Ans: A**

- get a good voltage profile
- compensate for line losses
- increase the voltage at the receiving end
- all

**Correct Ans: A**

- Rankine cycle
- Otto Cycle
- Carnot cycle
- Bell-Coleman cycle

**Correct Ans: A**

- improve power factor
- reduced peak demand
- run the equipment efficiently
- repair the machine

**Correct Ans: B**

- boron
- zirconium
- lead
- beryllium

**Correct Ans: A**

- Non-conventional power stations
- Basepower stations
- Major thermal stations
- Peaking hydro or gas turbine stations

**Correct Ans: A**

- average load/maximum load
- maximum load/connected load
- connected load/maximum load
- maximum load./average load

**Correct Ans: B**

- temperature rises and pressure remains unchanged
- temperature rises and pressure drops
- pressure rises and temperature drops
- pressure rises and temperature remains the same

**Correct Ans: A**

- over-excited synchronous motor
- induction motor
- under-excited synchronous motor
- commutator motor

**Correct Ans: A**

- voltage and power factor
- current
- voltage
- power factor

**Correct Ans: A**

- increase the sag and decrease the tension
- decrease the sag and increase the tension
- increase both
- decrease both

**Correct Ans: A**

- shunt capacitance to ground
- surface leakage currents
- series capacitance
- series and shunt capacitances

**Correct Ans: A**

- reduce fuel consumption
- increases steam production
- increase life of the boiler
- increase steam pressure

**Correct Ans: A**

- increased energy loss
- increased inductance
- increased reactance
- All the above

**Correct Ans: A**

- decrease in line length
- increase in diameter of the conductor
- increase in spacing between conductors
- increase in load current

**Correct Ans: C**

- increases
- decreases
- remains unaltered
- becomes infinite

**Correct Ans: A**

- long and unloaded
- long and loaded
- short and loaded
- none

**Correct Ans: A**

- length of the line
- the operating frequency of the line
- the conductivity of the conductors
- conductivity of the dielectric separating the conductors

**Correct Ans: A**

- corona performance of the line
- mechanically stability of the line
- appearance of the transmission line
- current carrying capacity of the line

**Correct Ans: A**

- provide stable interconnection
- increase the transmission capability
- decrease line losses
- reduce voltage drop

**Correct Ans: A**

- switched capacitor with controlled reactors
- fixed capacitor with controlled reactor
- switched capacitors
- saturable reactor with capacitor bank

**Correct Ans: A**

- the inductance will increase and the capacitance will decrease
- the inductance will increase and capacitance will remain unchanged
- both the inductance and capacitance will increase
- the inductance will decrease and the capacitance will increase

**Correct Ans: A**

- its current carrying capacity
- voltage drop in it
- operating voltage
- operating frequency

**Correct Ans: A**

- one fourth of original value
- equal to original value
- half the original value
- double the original value

**Correct Ans: A**

- process
- system
- software
- hardware

**Correct Ans: A**

- \(E\)
- \(\frac{1}{E^2}\)
- \(E^2\)
- \(\frac{1}{E}\)

**Correct Ans: B**

- equal to the area of phase conductor
- half of the area of phase conductor
- double the area of phase conductor
- 1.5 times the area of phase conductor

**Correct Ans: B**

- increasing the insulation resistance
- increasing the capacitance
- decreasing the capacitance
- increasing the conductor resistance

**Correct Ans: A**

- anyone
- mechanically injury
- crystallisation of lead through vibrations
- chemical action with impurities present in the soil when buried in earth

**Correct Ans: A**

- all
- real time data acquisition and processing
- data storing
- data monitoring and control

**Correct Ans: A**

- all
- SCADA
- communication between power station and substation
- communication between power station and load control center

**Correct Ans: A**

- single phase to ground
- phase-to-phase
- two-phase-to-ground
- three-phase to ground

**Correct Ans: A**

- the contact material with its vapour pressure and the circuit parameters
- the contact material only
- the contact material and its vapour pressure
- the circuit parameters only

**Correct Ans: A**

- damp out the fast transient
- reduce the magnitude of fault current
- control the CB operating time
- change the fault current power factor

**Correct Ans: A**

- compensate for voltage drop
- increase current
- reduce current
- reduce voltage drop

**Correct Ans: A**

- sub-transient state of short circuit current
- steady short circuit current
- transient state of short circuit current
- none

**Correct Ans: C**

- isolators
- circuit breakers
- load break switches
- circuit breakers and load break switches

**Correct Ans: A**

- reducing fault clearing time
- decreasing generator inertia
- single pole switching
- using double circuit line instead of single circuit line

**Correct Ans: D**

- natural draught
- induced draught
- forced draught
- balanced draught

**Correct Ans: A**

- equal to 1
- less than 1
- greater than 1
- none of the above

**Correct Ans: C**

- 100-200 ohms
- 20-40 ohms
- 70-80 ohms
- 500-1000 ohms

**Correct Ans: A**

- Mho's relay
- Impedance relay
- Reactance relay
- none

**Correct Ans: A**

- input torque
- losses
- reactance of generator
- reactance of transmission line

**Correct Ans: B**

- leads the voltage by \(90^\circ\)
- leads the voltage by \(180^\circ\)
- lags the voltage by \(90^\circ\)
- lags the voltage by \(180^\circ\)

**Correct Ans: A**

- absorbed by the circuit of relay
- required to operate the circuit breaker
- developed by the relay circuit
- none

**Correct Ans: A**

- zero current
- maximum current
- minimum voltage
- maximum voltage

**Correct Ans: A**

- bedding
- armour
- conductor surface
- lead sheath

**Correct Ans: D**

- becomes double
- becomes one-fourth
- becomes one-half
- remains unchanged

**Correct Ans: A**

- Rabindranath Tagore
- Lala Lajpat Rai
- Mahatma Gandhi
- Bal Gangadhar Tilak

**Correct Ans: A**

- Article 26
- Article 25
- Article 27
- Article 28

**Correct Ans: A**

- August 15,1995
- August 15,2000
- August 15,1992
- August 15,2001

**Correct Ans: A**

- \(137^{th}\)
- \(141^{st}\)
- \(133^{rd}\)
- \(155^{th}\)

**Correct Ans: A**

- \(1^{st}\) june
- \(3^{rd}\) june
- \(4^{th}\) june
- \(5^{th}\) june

**Correct Ans: A**

- Nani Palkhivala
- T.N.Kaul
- J.R.D.Tata
- Khushwant Singh

**Correct Ans: A**

- Sardar Vallabhbhai Patel
- Govind Ballabh Pant
- Jawaharlal Nehru
- Subhash Chandra Bose

**Correct Ans: A**

- Rabindranath Tagore
- C.V.Raman
- Dalai Lama
- Mother Teresa

**Correct Ans: A**

- Jagdish Singh Khehar
- T.S.Thakur
- H.L.Dattu
- Altamas Kabir

**Correct Ans: A**

- Bhupendrasinh Chudasma
- Vijaybhai Rupani
- Nitinbhai Patel
- Ganpatbhai Vasava

**Correct Ans: A**

- Atheist
- Theist
- Heretic
- Fanatic

**Correct Ans: A**

- Exposed
- Hidden
- Surreptitious
- Obscure

**Correct Ans: A**

- Stop
- Begin
- Create
- Dull

**Correct Ans: A**

- their
- they
- won't
- unless

**Correct Ans: A**

- can
- begin
- been
- being

**Correct Ans: A**

- play
- playing
- am playing
- am play

**Correct Ans: A**

- is having
- having
- have
- has

**Correct Ans: A**

- does the train leave?
- the train leaves?
- leaves the train?
- is the train leaving?

**Correct Ans: A**

- divergent
- independent
- modest
- adverse

**Correct Ans: A**

- Abolish
- Approve
- Allow
- Break

**Correct Ans: A**

Data will be available soon.

Subject | Number of questions |
---|---|

BASICS OF COMPUTER | 10 |

ELECTRICAL CIRCUIT ANALYSIS | 13 |

CONTROL SYSTEM ENGINEERING | 7 |

ELECTRICAL MACHINES | 9 |

POWER ELECTRONICS & DRIVES | 4 |

ENGINEERING MATHEMATICS | 8 |

MEASUREMENT & INSTRUMENTATION | 3 |

DIGITAL ELECTRONICS | 3 |

POWER SYSTEM | 6 |

ELECTROMAGNETICS | 3 |

BASIC ELECTRONICS | 2 |

SIGNALS & SYSTEMS | 2 |

ENGLISH | 10 |

GENERAL KNOWLEDGE | 10 |

GUJARATI | 10 |

Total | 100 |

- Long life
- Faster
- Used as cache memory
- Needs to be refreshed continuously

**Correct Ans: D**

- transport layer
- physical layer
- network layer
- application layer

**Correct Ans: A**

Statement A: Rogue security software is malicious software that mislead users to believe there is a computer virus installed on their computer or that their security measures are not up to date.

Statement B: When adware is downloaded without consent, it is considered malicious.

- Both Statement A & Statement B are True
- Statement A is True and Statement B is False
- Both Statement A & Statement B are False
- Statement A is False and Statement B is True

**Correct Ans: A**

- Pishing
- Dos attack
- Rootkit
- SQL Injection attack

**Correct Ans: B**

- Ultimate Native Indian Automatic Calculator
- Ultimate Native Indian Automatic Computer
- Universal Automatic Computing Device
- Universal Automatic Computer

**Correct Ans: D**

- Ctrl + Spacebar
- Control + Equal Sign
- Ctrl + Shift + Plus Sign
- Ctrl + End

**Correct Ans: C**

- network
- data link
- physical
- transport

**Correct Ans: D**

Statement A: The OS defines a job which has predefined sequence of commands, programs and data as a single unit.

Statement B: Jobs are processed not in the order of submission, i.e., last come first served fashion.

- Both Statement A and Statement B are True
- Statement A is True and Statement B is False
- Both Statement A and Statement B are False
- Statement A is False and Statement B is True

**Correct Ans: B**

- Distributed OS
- Time-Sharing OS
- Batch OS
- Networking OS

**Correct Ans: A**

- Turns extend mode on or off.
- Creates a chart of the data in the current range in a separate Chart sheet.
- Turns key tips on or off.
- Calculates all worksheets in all open workbooks.

**Correct Ans: C**

- 20 A
- 100 A
- 50 A
- 80 A

**Correct Ans: D**

- Active device which converts mechanical displacement in to a change of resistance
- Passive device which converts electrical displacement in to a change of resistance
- Passive device which converts mechanical displacement in to a change of resistance
- Active device which converts electrical displacement in to a change of resistance

**Correct Ans: C**

- Increase by a factor of 2
- Decrease by a factor of 2
- Increase by a factor of 4
- Remain same

**Correct Ans: D**

- 4 \(\times\) (per unit load power)
^{1/2} - (per unit load power)
^{1/2} - (per unit load power)/2
- 2 \(\times\) (per unit load power)

**Correct Ans: B**

- Double line fault
- Single line to ground fault
- Three phase fault
- Double line to ground fault

**Correct Ans: C**

- A circle with centre at (-1,0) and radius=1 in the anti-clockwise direction
- A semicircle with centre at (-1,0) and radius=1 in the clockwise direction
- A semicircle with origin as the centre and radius = 1 in the anti-clockwise direction
- A circle with origin as the centre and radius = 1 in the clockwise direction

**Correct Ans: D**

- \(0.2 \times (\frac{132}{220})^2\)
- \(0.1 \times (\frac{132}{220})^2\)
- \(0.2 \times (\frac{220}{132})^2\)
- \(0.1 \times (\frac{220}{132})^2\)

**Correct Ans: B**

\(Y_{bus} = j\begin{bmatrix}-7 & 2 & 3 & 0 \\2 & -12 & 4 & 2.5 \\3 & 4 & -9 & 2 \\0 & 2.5 & 2 & -4.5 \end{bmatrix}\)

- 1 and 2
- 1, 2 and 3
- 1 and 4
- 2 and 3

**Correct Ans: A**

- infinity
- 1
- 0.5
- 0

**Correct Ans: B**

- \(\frac{1-e^{-t}}{t}\)
- \(\frac{1-e^t}{t}\)
- \(\frac{1+e^{-t}}{2t}\)
- \(\frac{1+e^t}{t}\)

**Correct Ans: A**

- time invariant system
- non-invertible system
- causal system
- invertible system

**Correct Ans: D**

- decrease by 5%
- increase by 10%
- increase by 5%
- decrease by 10%

**Correct Ans: C**

- 0.5 A and 400 \(\Omega\)
- 0.25 A and 800 \(\Omega\)
- 0.5 A and 800 \(\Omega\)
- 0.25 A and 400 \(\Omega\)

**Correct Ans: B**

- an open circuit
- a constant current source
- a short circuit
- a constant voltage source

**Correct Ans: B**

- f
- f/2
- 2f
- 3f

**Correct Ans: B**

- \(z\frac{\partial z}{\partial x} + y\frac{\partial z}{\partial y}=z(x+y)\)
- \(z\frac{\partial z}{\partial x} + (2x-y)\frac{\partial z}{\partial y}=z\)
- \(z\frac{\partial z}{\partial x} + (2x+y)\frac{\partial z}{\partial y}=x-y\)
- \(z\frac{\partial z}{\partial x} + (2x-y)\frac{\partial z}{\partial y}=x+y\)

**Correct Ans: B**

- -3
- \(\frac{1}{3}\)
- \(-\frac{1}{3}\)
- 3

**Correct Ans: A**

- \(K=M\sqrt{L_1^2+L_2^2}\)
- \(K=M\sqrt\frac{L_2}{L_1}\)
- \(K=\frac{M}{\sqrt{L_1L_2}}\)
- \(K=M\sqrt{L_1L_2}\)

**Correct Ans: C**

- \(-\frac{1}{2},\:2\)
- \(-\frac{1}{2},\:-2\)
- \(\frac{1}{2},\:2\)
- \(\frac{1}{2},\:-2\)

**Correct Ans: C**

- 3
- 7
- 4
- 0

**Correct Ans: C**

- 2
- 3
- 5
- 4

**Correct Ans: D**

- \(\sqrt\frac{2}{\pi} \frac{2as}{a^2+s^2}\)
- \(\sqrt\frac{2}{\pi} \frac{s}{a^2-s^2}\)
- \(\sqrt\frac{2}{\pi} \frac{s}{a^2+s^2}\)
- \(\sqrt\frac{2}{\pi} \frac{s}{1+a^2s^2}\)

**Correct Ans: C**

- back emf Eb is equal to the applied voltage V
- back emf Eb is inversely proportional to the applied voltage V
- back emf Eb is equal to square of the applied voltage V
- back emf Eb is equal to half the applied voltage V

**Correct Ans: D**

- Q and δ
- V and δ
- P and V
- P and Q

**Correct Ans: C**

- 120 degree
- 45 degree
- 90 degree
- 0 degree

**Correct Ans: C**

- 0.04
- 0.06
- 0
- 0.02

**Correct Ans: C**

- 5 V
- 15 V
- 10 V
- 20 V

**Correct Ans: C**

- 25 Hz
- 100 Hz
- 50 Hz
- 75 Hz

**Correct Ans: C**

- two half subtractors
- two half subtractors and a NOT gate
- two half subtractors and an AND gate
- two half subtractors and a OR gate

**Correct Ans: D**

- Fault Current \(\frac{I_f}{3}\)
- Fault Current \(I_f\)
- 3\(\times\) Fault Current \(I_f\)
- Zero

**Correct Ans: D**

- 200 A
- 100 A
- 150 A
- 50 A

**Correct Ans: B**

- \( C_u = \frac{R_2}{C_1} R1, R_u = \frac{C_1}{R_2} C3 \)
- \( C_u = \frac{R_2}{C_3} R_1, R_u = R_2 \frac{C_3}{C_1} \)
- \( C_u = \frac{C_1}{C_3}, R_u = \frac{R_2}{R_1} \)
- \( C_u = C_3 \frac{R_1}{R_2}, R_u = R_2 \frac{C_1}{C_3} \)

**Correct Ans: D**

- Faraday's law
- Coulomb's law
- Gauss's law
- Biot-Savart's law

**Correct Ans: C**

- 4%, 20 Hz
- 2%, 100 Hz
- 3%, 50 Hz
- 4%, 2 Hz

**Correct Ans: D**

- \(\frac{1}{2}\)
- \(-\frac{1}{2}\)
- \(-\frac{3}{2}\)
- \(\frac{3}{2}\)

**Correct Ans: B**

- \(V_s /(1 +\alpha)\)
- \(V_s (1 +\alpha)\)
- \(V_s (1 - \alpha)\)
- \(V_s /(1 - \alpha)\)

**Correct Ans: D**

- \(x^2=4cy\)
- \(x^2+y^2=4c^2\)
- \(4xy=c^2\)
- \(xy=4c^2\)

**Correct Ans: C**

- 3 (all 2-inputs)
- 3 (two with 2-inputs & one with 3-inputs)
- 3 (all 3-inputs)
- 3 (one with 2-inputs & two with 3-inputs)

**Correct Ans: B**

- P/4
- P/2
- 4P
- 2P

**Correct Ans: A**

- \({G_1}{G_2} - {G_2} - 1\)
- \({G_1}{G_2} + {G_2} + 1\)
- \(\frac{{G_1}{G_2}} {(1-{G_1}{G_2})}\)
- \(\frac{{G_1}{G_2}} {(1+{G_1}{G_2})}\)

**Correct Ans: A**

- 50 W
- 100W
- 150 W
- 200 W

**Correct Ans: C**

- \(\bar{P} = \bar{E} \cdot \bar{H}\)
- \(\bar{P} = \frac{1}{2} \bar{E} \times \bar{H^{*}}\)
- \(\bar{P} = \bar{E} \times \bar{H}\)
- \(\bar{P} = \bar{E} \times \bar{H^{*}}\)

**Correct Ans: B**

- MMF = Flux / Reluctance
- Flux = 1 + (Reluctance / MMF)
- Reluctance = MMF \(\times\) Flux
- MMF = Flux \(\times\) Reluctance

**Correct Ans: D**

- \( V_A = 200 V \: and \: V_B = 200 V \)
- \( V_A = 80 V \: and \: V_B = 120 V \)
- \( V_A = 120 V \: and \: V_B = 120 V \)
- \( V_A = 80 V \: and \: V_B = 80 V \)

**Correct Ans: B**

- \(\alpha > 0 \:and\: \alpha \beta < 3 \)
- \(\alpha > 0 \:and\: \alpha \beta > 3 \)
- \(\alpha < 0 \:and\: \alpha \beta > 3 \)
- \(\alpha < 0 \:and\: \alpha \beta < 3 \)

**Correct Ans: B**

- 0.5
- 0
- 1
- 0.866

**Correct Ans: D**

- \(f_2- f_1\)
- \(\frac{f_1}{f_2}\)
- \(f_2 + f_1\)
- \(\frac{f_2}{f_1}\)

**Correct Ans: A**

- \(\frac{\pi}{2}\)
- \(\frac{1}{\pi}\)
- \(\pi\)
- \(\frac{2}{\pi}\)

**Correct Ans: C**

the load is______________.

- 1000 W
- 250 W
- 750 W
- 500 W

**Correct Ans: C**

- 15 \(\Omega\)
- 45 \(\Omega\)
- 5 \(\Omega\)
- 30 \(\Omega\)

**Correct Ans: C**

**Correct Ans: A**

- 1
- 0.25
- 0.577
- 0.75

**Correct Ans: C**

- \(\alpha = \frac{\beta}{\beta \:-\: 1} \)
- \(\beta = \frac{\alpha}{\alpha \:-\:1 } \)
- \(\alpha = \frac{\beta}{1 \:-\: \beta} \)
- \(\beta = \frac{\alpha}{1 \:+\: \alpha} \)

**Correct Ans: B**

- East
- North
- West
- South

**Correct Ans: D**

\(\begin{bmatrix}\dot {x_1} \\ \dot {x_2} \end{bmatrix} =\begin{bmatrix}-3 & -1 \\ 2 & 0 \end{bmatrix} \begin{bmatrix} {x_1} \\ {x_2} \end{bmatrix} + \begin{bmatrix} 1 \\ 0 \end{bmatrix} u \quad and\)

\(y=\begin{bmatrix} 1 & 0 \end{bmatrix} \begin{bmatrix} {x_1} \\ {x_2} \end{bmatrix} + \begin{bmatrix} 1 \\ 0 \end{bmatrix} u \quad \) is

- Observable but not Controllable
- Controllable and Observable
- neither Controllable nor Observable
- Controllable but not Observable

**Correct Ans: B**

- \(y=5x+\log{x}\)
- \(y=5x-5+\log{x}\)
- \(y=\log{x}\)
- \(y=5+\log{x}\)

**Correct Ans: C**

- Full load × \( \sqrt{\frac{B}{A}}\)
- Full load × ( \(\frac{B}{A}\) )
- Full load × ( \(\frac{A}{B}\) )
- Full load × \( \sqrt{\frac{A}{B}}\)

**Correct Ans: A**

- 18 \(\mu\)F
- 9 \(\mu\)F
- 3 \(\mu\)F
- 2 \(\mu\)F

**Correct Ans: D**

- A(B+C+D)
- A(BC+D)
- A+(B+C)D
- A+B+C+D

**Correct Ans: B**

- \(-\frac{3}{2}\)
- \(\frac{5}{2}\)
- \(\frac{9}{2}\)
- \(-\frac{7}{2}\)

**Correct Ans: C**

If you enlarge your laptop screen, \(\underline{\smash{it\: is\: much\: easy\: to\: seeing \:the\: photos}}\) than if you keep then smaller

- it is most easier to see the photos
- The given sentence is correct
- it is much easier for see the photos
- it is much easier to see the photos

**Correct Ans: D**

- Intermitent
- Malpractice
- Obligatary
- Recomended

**Correct Ans: B**

Jean is going to depart ________ 7 p.m From our place.

- on
- in
- over
- at

**Correct Ans: D**

Today is _________third day of our annual meeting.

- No article
- an
- the
- a

**Correct Ans: C**

P: is intended to give our readers an idea of the onerousness

Q: the special Supplement which we are issuing today

R: on which the people of India are setting out

S: as well as the grandeur of the great adventure

- SPQR
- RQSP
- RQPS
- QPSR

**Correct Ans: D**

- Allowed
- Closed
- Refused
- Banned

**Correct Ans: A**

- Continuance
- Quadilateral
- Wearysome
- Affluant

**Correct Ans: A**

Completing a period of hundred years.

- protocol
- Centennial
- Flounder
- Universal

**Correct Ans: B**

- Empty
- Charged
- Unifilled
- Enlarge

**Correct Ans: B**

(Avoid punctuation errors)

(A) Either Ram or I / (B) am ready to / (C) completes this task / (D) NO ERROR

- C
- A
- D
- B

**Correct Ans: A**

- Justice Sharad Arvind Bobde
- Justice Kurian Joseph
- Justice Madan Lokur
- Justice Dipak Misra

**Correct Ans: A**

- Dichloro Diphenyl Tri-chloromethane
- Dichloro Diphenyl Tri-chloroethane
- Diamino Diphenyl Tri-chloroethane
- Dibromo Diphenyl Tri-chloroethane

**Correct Ans: B**

- North America
- Europe
- Africa
- Asia

**Correct Ans: A**

- Bangladesh
- United States of America
- England
- China

**Correct Ans: B**

- Greenwich Mean Time
- Greenwich Management Time
- Greenwich Meridian Time
- Greenwich Measurement Time

**Correct Ans: A**

- Punjab
- Himachal Pradesh
- Haryana
- Uttarakhand

**Correct Ans: A**

- Calcutta
- Lahore
- Allahabad
- Madras

**Correct Ans: B**

- Neha Gupta
- Greta Thunberg
- Kehkashan Basu
- Malala Yousafzai

**Correct Ans: B**

- 2011-12
- 2018-19
- 1991-92
- 2004-05

**Correct Ans: A**

- P. V. Sindhu
- Sakshi Malik
- P. T. Usha
- Karnam Malleswari

**Correct Ans: D**

- લાધવ X ગૌરવ
- ઉગ્ર X શાંત
- જન્નત X જહન્નમ
- રચનાત્મક X ખંડનાત્મક

**Correct Ans: A**

- સાળી
- સાળાવેલી
- બનેવી
- બહેન

**Correct Ans: B**

- કોઈએ હરીશને બોલતા રોક્યો નહિ.
- હરીશ કોઈનાથી રોકાયા વિના બોલતો રહ્યો.
- હરીશને બોલતા કોઈનાથી રોકી શકાયો નહિ.
- હરીશ કોઈના વડે બોલતો રોકાયો નહિ.

**Correct Ans: A**

- આમ્ર વૃક્ષ
- બોધિવૃક્ષ
- કલ્પવૃક્ષ
- કદમ્બવૃક્ષ

**Correct Ans: C**

- પ્રેરક
- કર્મણી
- આજ્ઞાર્થ
- ભાવે

**Correct Ans: A**

- વાલોળ
- પૈસાદાર
- વહેલા
- હિતેશ્રી

**Correct Ans: D**

- જ્યારથી.... ત્યારથી
- જેમ....તેમ
- જ્યારે.... ત્યારે
- જો....તો

**Correct Ans: A**

જોરાવરસિંહ નામનો એક ખૂંખાર બહાર વટિયો થઈ ગયો.

- બહાર વટિયો
- જોરાવરસિંહ નામનો
- થઈ ગયો
- એક ખૂંખાર

**Correct Ans: A**

- વયસ્ક
- વ્યક્તિગત
- સામુદાયિક
- નૈતિક

**Correct Ans: C**

ભૂમિ ભણવામાં લક્ષ્ય આપતી નથી.

- ભુમિ
- કોઈ સુધારો નહીં
- ભૂમિ
- લક્ષ

**Correct Ans: D**

Subject | Number of questions |
---|---|

GENERAL KNOWLEDGE | 10 |

GUJARATI | 10 |

ENGLISH | 10 |

ENGINEERING MATHEMATICS | 7 |

ELECTRICAL CIRCUIT ANALYSIS | 12 |

SIGNALS & SYSTEMS | 4 |

CONTROL SYSTEM ENGINEERING | 7 |

ELECTROMAGNETICS | 4 |

ELECTRICAL MACHINES | 9 |

POWER ELECTRONICS & DRIVES | 5 |

BASIC ELECTRONICS | 1 |

DIGITAL ELECTRONICS | 3 |

MEASUREMENT & INSTRUMENTATION | 3 |

POWER SYSTEM | 5 |

BASICS OF COMPUTER | 10 |

Total | 100 |

- \(15^{th}\) August
- \(26^{th}\) November
- \(25^{th}\) December
- \(26^{th}\) January

**Correct Ans: D**

- Odisha
- Kerala
- Maharashtra
- Telangana

**Correct Ans: B**

- Mixed Economy
- Capitalist Economy
- Socialist Economy
- Communist Economy

**Correct Ans: A**

- March
- June
- September
- December

**Correct Ans: C**

- Asia-Pacific free Trade Agreement
- ASEAN Free Trade Agreement
- African Continental Free Trade Agreement
- North American Free Trade Agreement

**Correct Ans: D**

- Ram Nath Kovind
- Girish Chandra Murmu
- Karan Singh
- Satya Pal Malik

**Correct Ans: B**

- Pakistan
- Myanmar
- Bhutan
- Bangladesh

**Correct Ans: A**

- PV Sindhu
- PT Usha
- KD Jadhav
- Abhinav Bindra

**Correct Ans: C**

- Giant Positioning system
- Global positioning System
- Global positioning Satellites
- Giant Positioning Satellite

**Correct Ans: B**

- International Union for Conventions on Nature
- Institute for Universal Conventions of Nature
- Institute for Universal Conservation of Nature
- International Union for Conservation of Nature

**Correct Ans: D**

Sony is _______most expensive brand I've ever heard of in my life.

- a
- an
- the
- No article

**Correct Ans: C**

She likes to drink tea______the morning.

- on
- in
- at
- over

**Correct Ans: B**

(A) Raju wastes not / (B) only money / (C) but also his life / (D) NO ERROR

- A
- B
- C
- D

**Correct Ans: D**

- Hate
- Admiration
- Approval
- Sympathy

**Correct Ans: A**

- Recant
- Renounce
- Allow
- Retract

**Correct Ans: C**

Accidental good fortune

- Accomplice
- Fluke
- Brood
- Shell

**Correct Ans: B**

- Carefullness
- Laboriuous
- Hortikulture
- Implicit

**Correct Ans: D**

- Fortunately
- Genaralization
- Equiliateral
- Witnesed

**Correct Ans: A**

I \(\underline{\mathbf{refuse\: to\: watch\: news \:in\: television\: anymore}}\) because of how broadcasters amplify bad news in a way that causes unnecessary problems

- refuse to watching news in television anymore
- refused to watch news in television nomore
- refuse to watch news in television anymore
- The given sentence is correct

**Correct Ans: C**

P: Kobe Bryant killed along with his 13-year-old daughter Gianna

Q: and other in a helicopter crash

R: the news of retired basketball superstar

S: has shocked the world

- RPSQ
- RPQS
- PQRS
- PQSR

**Correct Ans: B**

- \(8A+14I\)
- \(-8A-14I\)
- \(8A-14I\)
- \(-8A+14I\)

**Correct Ans: C**

- \(y^2=x+4\)
- \(y^2=4x+1\)
- \(y^2=4x-1\)
- \(y^2=4(x+1)\)

**Correct Ans: D**

- \(\frac{1}{4}\)
- \(\frac{xy}{4}\)
- \(\frac{3xy}{4}\)
- \(\frac{3}{4}\)

**Correct Ans: D**

- \(2\pi\)
- -2
- 2
- \(\frac{\pi}{2}\)

**Correct Ans: C**

- \(-\frac{e^{-2t}\sin t}{2}\)
- \(-\frac{e^{-2t}\:t\cos t}{2}\)
- \(\frac{e^{-2t}\:t\sin t}{2}\)
- \(\frac{e^{-2t}\sin t}{2}\)

**Correct Ans: B**

- \(6u=1\)
- \(u=6\)
- \(v=6u\)
- \(v^2=6u\)

**Correct Ans: A**

- \(\frac{e^{-3t}}{\sqrt t}\)
- \(\frac{e^{-3t}}{\sqrt {\pi t}}\)
- \(\frac{e^{3t}}{t^2}\)
- \(\frac{e^{3t}}{\pi t}\)

**Correct Ans: B**

- \(\frac{25}{2}\)
- \(\frac{5}{\sqrt{2}}\)
- \(\frac{25}{4}\)
- \(\frac{5}{2}\)

**Correct Ans: B**

- \(\frac{2}{\pi\:n^2}\)
- \(\frac{2}{\sqrt{\pi\:n}}\)
- \(\frac{\sqrt{2}}{\pi\:n}\)
- \(\sqrt{\frac{2}{\pi}}\frac{1}{n}\)

**Correct Ans: C**

- \(\frac{\partial^2 z}{\partial x^2}+\frac{\partial z}{\partial t}-2\frac{\partial^2 z}{\partial t^2}=0\)
- \(\frac{\partial z}{\partial x}+\frac{\partial z}{\partial y}=\frac{\partial^2 z}{\partial x \partial t}\)
- \(\frac{\partial^2 z}{\partial x^2}+\frac{\partial^2 z}{\partial x \partial t}-2\frac{\partial^2 z}{\partial t^2}=0\)
- \(\frac{\partial^2 z}{\partial x^2}+2\frac{\partial^2 z}{\partial x \partial t}+\frac{\partial^2 z}{\partial t^2}=0\)

**Correct Ans: A**

- 0.1 A and 20 W
- 0.2 A and 64 W
- 0.3 A and 72 W
- 0.5 A and 95 W

**Correct Ans: C**

- 1 A
- 2 A
- 3 A
- 4 A

**Correct Ans: C**

- \(\frac{\phi_i}{\phi_g}\)
- \(\phi_i\times\phi_g\)
- \(\phi_i-\phi_g\)
- \(\phi_i+\phi_g\)

**Correct Ans: A**

- 0
- 0.5
- 0.8
- 1

**Correct Ans: D**

- 0
- 0.5
- 0.866
- 1

**Correct Ans: B**

- all independent voltage sources and current sources are short circuited
- all independent voltage sources are short circuited and all independent current sources are open circuited
- all independent voltage sources are open circuited and all independent current sources are short circuited
- all independent voltage sources and current sources are open circuited

**Correct Ans: B**

- 25%
- 50%
- 75%
- 100%

**Correct Ans: B**

- 5 mH
- 10 mH
- 25 mH
- 50 mH

**Correct Ans: A**

- minimum, maximum
- maximum, minimum
- minimum, minimum
- maximum, maximum

**Correct Ans: A**

- \(R=2\sqrt \frac{L}{C}\)
- \(R<2\sqrt \frac{L}{C}\)
- \(R>2\sqrt \frac{L}{C}\)
- \(R=0\)

**Correct Ans: B**

- \(- \infty\) and \(\infty\)
- 0 and 1
- \(- \infty\) and 1
- 0 and \(- \infty\)

**Correct Ans: A**

- Remain stationary
- Move in an opposite direction
- Move in the direction of the field
- Start spinning

**Correct Ans: A**

- 8 \(\mu F\)
- 20 \(\mu F\)
- 30 \(\mu F\)
- 32 \(\mu F\)

**Correct Ans: C**

- Curl(H) = J
- Curl(D) = J
- Curl(B) = I
- Curl(V) = I

**Correct Ans: A**

- 9
- 6
- 3
- 2

**Correct Ans: D**

- 0 degree
- 90 degree
- 120 degree
- 150 degree

**Correct Ans: B**

- 475 W
- 950 W
- 1250 W
- 2050 W

**Correct Ans: D**

- 110 V
- 220 V
- 440 V
- 660 V

**Correct Ans: A**

- 0
- 0.02
- 0.04
- 0.06

**Correct Ans: D**

- 25 Hz
- 50 Hz
- 60 Hz
- 100 Hz

**Correct Ans: D**

- 180V
- 200 V
- 220 V
- 240V

**Correct Ans: B**

- 6 Ω
- 12 Ω
- 30 Ω
- 150 Ω

**Correct Ans: A**

- 100 W
- 200 W
- 400 W
- 800 W

**Correct Ans: B**

- 0
- 0.3
- 0.5
- 1

**Correct Ans: D**

- source, drain and gate
- emitter, base and collector
- base, source and drain
- gate, emitter and collector

**Correct Ans: A**

- \(\pi\)
- \(\alpha\)
- \(\pi - \alpha \)
- \(\pi + \alpha \)

**Correct Ans: C**

- 50 \(\mu s\)
- 100 \(\mu s\)
- 200 \(\mu s\)
- 400 \(\mu s\)

**Correct Ans: B**

- \(\pi V_{dc}\)
- \(2\pi V_{dc}\)
- \(\frac {V_{dc}}{\pi}\)
- \(\frac {2 V_{dc}}{\pi}\)

**Correct Ans: D**

- fixed alternating voltage directly to variable alternating voltage without a change in the

frequency - fixed alternating voltage directly to variable alternating voltage with a change in the frequency
- variable alternating voltage directly to constant dc voltage without a change in the frequency
- variable alternating voltage directly to constant dc voltage with a change in the frequency

**Correct Ans: A**

- Non-causal system
- Non-invertible system
- Time variant system
- Non-line ar system

**Correct Ans: B**

- \(y(n) = x(n) + 5y(n-1) \)
- \(y(n) = x(n) - 5y(n-1) \)
- \(y(n) = 2x(n) + 5y(n-1) \)
- \(y(n) = 2x(n) - 5y(n-1) \)

**Correct Ans: C**

- 50 Hz
- 75 Hz
- 100 Hz
- 150 Hz

**Correct Ans: A**

- 1 V
- 5 V
- 11 V
- 15

**Correct Ans: C**

- two half adders
- two half adders and a NOT gate
- two half adders and an AND gate
- two half adders and an OR gate

**Correct Ans: D**

- \(Y=AB+C(D+E)\)
- \(Y=AB+C+DE\)
- \(\bar A + \bar B + \bar C + \bar D+ \bar E\)
- \((\bar A + \bar B ) C + \overline {DE}\)

**Correct Ans: D**

- J=0, K=0
- J=0, K=1
- J=1, K=0
- J=1, K=1

**Correct Ans: A**

- \( L_u = C_1 R_2 R_3, \: R_u = C_1 \frac{R_2}{C_3} \)
- \(L_u = C_3 \frac{R_3}{R_2}, \: R_u = C_1 \frac{R_2}{C_3} \)
- \( L_u = C_1 C_3, \: R_u = R_3 R_2 \)
- \( L_u = C_3 \frac{R_2}{C_1}, \: R_u = C_1 R_ 2 \)

**Correct Ans: A**

- Strain gauge
- LVDT
- Thermistor
- Piezoelectric transducer

**Correct Ans: D**

- 1 mV
- 0.1 V
- 0.5 V
- 1 V

**Correct Ans: A**

- 0.05 pu
- 0.5 pu
- 5 pu
- 50 pu

**Correct Ans: C**

- 450
- 500
- 750
- 1000

**Correct Ans: A**

- 11 * 11
- 15 * 15
- 24 * 24
- 30 * 30

**Correct Ans: C**

- increasing the transfer reactance
- single pole switching of circuit breakers
- phase shifting transformer
- None of the above

**Correct Ans: B**

- Three phase
- Single line to ground
- Double Line
- Double line to ground

**Correct Ans: B**

- 0
- \(I_a\)
- \(3I_a\)
- \(\frac{I_a}{3}\)

**Correct Ans: A**

- \(G_1(s)G_2(s)\)
- \(\frac{G_1(s)}{G_2(s)}\)
- \(G_1(s){\left( {\frac{{1}}{{G_1(s)}}+G_2(s)} \right)}\)
- \(G_1(s){\left( {\frac{{1}}{{G_1(s)}}-G_2(s)} \right)}\)

**Correct Ans: B**

- 1,1
- 1,2
- 0,0
- 2,1

**Correct Ans: C**

Where b is an unknown constant. This system is

- Observable for all values of b
- Observable for all non-zero values of b
- Unobservable for all values of b
- Unobservable for all non-zero values of b

**Correct Ans: B**

**Correct Ans: A**

**Correct Ans: C**

- UNIVACI
- ENIAC 1
- Mark I
- IBM 701

**Correct Ans: C**

- Security
- Control over system performance
- Job accounting
- Error detecting aids

**Correct Ans: C**

- Authorization
- Authentication
- Automation
- Security

**Correct Ans: B**

- Non-volatile
- cannot be accidentally changed
- cheaper than RAMS
- Used as cache memory

**Correct Ans: D**

- Font - Style
- Font - Effects
- Font - Size
- Font - Underline style

**Correct Ans: B**

- Shift+F9
- Ctrl+Shift+End
- Ctrl+End
- Ctrl+Shift+U

**Correct Ans: D**

- Worm
- Port Scanning
- Denial of Service
- Program

**Correct Ans: A**

- Man-in-the-middle attacks
- DDOS attacks
- SQL Injection attacks
- Rootkit attacks

**Correct Ans: A**

- Framing & Link access
- End-to-end delivery
- Reliable delivery
- Addressing

**Correct Ans: A**

- Plain Text
- Digital Signature
- Ciphertext
- Decryption

**Correct Ans: B**

- ઉપેક્ષા
- અપેક્ષા
- આજ્ઞા
- તિતિક્ષા

**Correct Ans: A**

- અરૂણોદય
- અનિર્હશ
- અહર્નિશ
- અમૂલખ

**Correct Ans: C**

- આજીજી કરવી
- આંસુ લૂછવા
- ઘણું વહાલ દર્શાવવું
- અપશબ્દ બોલવા

**Correct Ans: C**

- સૂતર
- ચહેરો
- શરત
- સ્ત્રી

**Correct Ans: B**

ભક્તિ, મોક્ષ, પ્રભાત, જ્ઞાન

- મોક્ષ
- પ્રભાત
- ભક્તિ
- જ્ઞાન

**Correct Ans: D**

- દેશનું ગૌરવ વધારવું એ એમની ફરજ છે.
- દેશનું ગૌરવ વધારવું એ આપણેની ફરજ છે.
- દેશનું ગૌરવ વધારવું એ આપણી ફરજ છે.
- દેશનું ગૌરવ વધારવું એ હમને ફરજ છે.

**Correct Ans: C**

1 . મેં સપનાનું સ્વાગત કર્યું.

2 . મેં સપનાનું સારું સુસ્વાગત કર્યું.

- 1 અને 2 બંને સાચા છે.
- 1 સાચું છે.
- 2 સાચું છે.
- 1 અને 2 બંને ખોટા છે.

**Correct Ans: B**

- ત્રિલોકે પત્ર વંચાવ્યો
- ત્રિલોક મારફત પત્ર વંચાયો
- ત્રિલોકથી પત્ર વંચાય છે.
- ત્રિવેણી ત્રિલોક પાસે પત્ર વંચાવે છે.

**Correct Ans: D**

- ગંભીર
- નકાર
- ઉદ્વાર
- વિધાન

**Correct Ans: C**

- કર્મણિ
- ભાવે
- કર્તરિ
- પ્રેરક

**Correct Ans: A**

Subject | Number of questions |
---|---|

BASICS OF COMPUTER | 10 |

ENGINEERING MATHEMATICS | 6 |

ELECTRICAL CIRCUIT ANALYSIS | 9 |

ELECTRICAL MACHINES | 10 |

DIGITAL ELECTRONICS | 2 |

POWER SYSTEM | 4 |

ELECTROMAGNETICS | 6 |

MEASUREMENT & INSTRUMENTATION | 4 |

SIGNALS & SYSTEMS | 4 |

CONTROL SYSTEM ENGINEERING | 4 |

POWER ELECTRONICS & DRIVES | 8 |

BASIC ELECTRONICS | 3 |

ENGLISH | 10 |

GENERAL KNOWLEDGE | 10 |

GUJARATI | 10 |

Total | 100 |

- URL
- number address
- network protocol
- bandwidth

**Correct Ans: C**

**Solution:**

- managing
- processing
- controlling
- booting

**Correct Ans: D**

**Solution:**

- kernel
- shell
- memory
- device driver

**Correct Ans: D**

**Solution:**

- serial transmission
- virtual transmission
- synchronous transmission
- parallel transmission

**Correct Ans: A**

**Solution:**

- scatter
- pie
- stock
- area

**Correct Ans: A**

**Solution:**

- .doc and .xls
- .exe and .com
- .ppt and .pxs
- .y2k and .wmk

**Correct Ans: B**

**Solution:**

- ROM
- SRAM
- DRAM
- RAM

**Correct Ans: A**

**Solution:**

- Pivot table
- Autosum
- Autofill
- Charts

**Correct Ans: D**

**Solution:**

- Kaspersky
- Spyware
- Skrenta
- Spam

**Correct Ans: B**

**Solution:**

- Artificial Intelligence
- Integrated circuit
- Vacuum tubes
- Transistors

**Correct Ans: B**

**Solution:**

- \( \frac{23}{105} \)
- \( \frac{19}{105} \)
- \( \frac{26}{105} \)
- \( \frac{17}{105} \)

**Correct Ans: C**

**Solution:**

\( \int_0^1{\int_0^{x^2}{(x^2+y^2)}} \: dy \: dx \)

= \( \int_0^1 [x^2 y + \frac{y^3}{3}]_0^{{x}^{2}} dx \)

= \( \int_0^1 [x^4 + \frac{x^6}{3}] dx\)

= \([\frac{x^5}{5} + \frac{x^7}{21}]_0^1\)

= \([\frac{1}{5} + \frac{1}{21}]\)

=\(\frac{26}{105}\)

- \(-\infty \leq r < 0 \)
- \( 0 \leq r < 1 \)
- \( 0 \leq r < \infty \)
- \( -1 \leq r < 0 \)

**Correct Ans: C**

**Solution:**

\(\Rightarrow\) In spherical coordinate system 'r' is the distance of point P from origin and so \( 0 \leq r < \infty \)

- Push-pull complementary amplifier
- Complementary MOS amplifier
- Common emitter amplifier
- Emitter coupled amplifier

**Correct Ans: A**

**Solution:**

\(\Rightarrow\) The push-pull amplifier increases the output voltage and current delivering capability of the operational amplifier.

- 1
- 0.0035
- 0.1
- 0.5

**Correct Ans: A**

**Solution:**

\(\mathbf{Given \:data:}\)

\(W_1=W_2=600\:W\)

\(\mathbf{ Measurement\:of\:Power\:and\:Power\:factor\:by\:Two\:Wattmeter\:Method\:in\:a\:balanced\:three\:phase\:load}\)

\(Wattmeter\: reading\: W_1=V_LI_L\cos(30^\circ-\phi)....(1)\)

\(Wattmeter\: reading \:W_2=V_LI_L\cos(30^\circ+\phi)....(2)\)

\(Using\: equation\:(1)\:and\:(2)\)

\(Total\:power\:absorbed\:in\:a\:three\:phase\:W=W_1+W_2=\sqrt3V_LI_L\cos\phi....(3)\)

\(W_1-W_2=V_LI_L\sin\phi....(4)\)

\(Using\: equation\:(3)\:and\:(4)\)

\(\frac{W_1-W_2}{W_1+W_2}=\frac{V_LI_L\sin\phi}{\sqrt3V_LI_L\cos\phi}\)

\(\tan\phi=\sqrt3[\frac{W_1-W_2}{W_1+W_2}]....(5)\)

\(\phi=\tan^{-1}[\frac{\sqrt3(W_1-W_2)}{W_1+W_2}]....(6)\)

Values \(W_1=W_2=600\:W\) put in equation (6)

\(\phi=\tan^{-1}(0)\implies \phi=0\)

\(Power\:factor=\cos\phi=\cos0=1\)

Therefore,In measurement of 3-phase power by two wattmeter method, both wattmeter readings are equal. The power factor of the load is unity.

1. Energy of a power signal is infinite.

2. Power of an energy signal is zero.

- Both statements are false
- Statement 1 is false and statement 2 is true
- Both statements are true
- Statement 1 is true and statement 2 is false

**Correct Ans: C**

**Solution:**

\(\Rightarrow \mathbf{Energy\: Signal}\) is a signal whose energy is finite and power is zero.

\(\Rightarrow \mathbf{Power\: Signal}\) is a signal whose power is finite and energy is infinite.

- 230 A
- 46 A
- 23 A
- 460 A

**Correct Ans: D**

**Solution:**

\(\Rightarrow\) Starting current of DC motor is given by

\( I_{ast} = \frac{V}{R_a} \)

\( I_{ast} = \frac{230}{0.5} = 460 \: A \)

- triple quadrant operation
- single quadrant operation
- four quadrant operation
- double quadrant operation

**Correct Ans: B**

**Solution:**

\(\Rightarrow\) The half controlled converter can provide positive output voltage and current only.

\(\Rightarrow\) Hence it can provide single quadrant operation only.

- RC triggering
- UJT triggering
- Resistance triggering
- Snubber triggering

**Correct Ans: D**

**Solution:**

\(\Rightarrow\) Snubber circuit is used to limit high dv/dt in SCR

\(\Rightarrow\) High dv/dt can cause malfunctioning of SCR.

- CMOS
- TTL
- IGFET
- Emitter follower

**Correct Ans: D**

**Solution:**

\(\Rightarrow\) Emitter follower has unity gain.

\(\Rightarrow\) So emitter follower only provides impedance transformation without affecting the magnitude of signal.

- The amount of copper or aluminium wires required to transfer the given amount of power is more in a three-phase system than that is required in a single-phase system.
- In a three-phase system, power never falls to zero.
- A three-phase system has better voltage regulation.
- A three-phase machine gives more output compared to a single-phase machine of the same size.

**Correct Ans: A**

**Solution:**

\(\mathbf{Advantages \:of \:Three\: Phase\: System:}\)

\(\mathbf{1.}\) Three phase system requires only 75% weight of conducting materials of that required by single phase system to transmit the same amount of power at a given voltage and over a given distance.

\(\mathbf{2.}\) Three phase system is more capable and reliable than single phase system.

\(\mathbf{3.}\) A three-phase machine gives more output compared to a single-phase machine of the same size.

\(\mathbf{4.}\) A three-phase system has better voltage regulation.

- Maximum
- 50%
- 25%
- Minimum

**Correct Ans: A**

**Solution:**

\(\Rightarrow\) Maximum Efficiency occurs when Copper Loss = Iron Loss

$$\begin{bmatrix} 0 & 5 \\ -5 & 0 \end{bmatrix}$$

- \(\begin{bmatrix} -5 & 0 \\ 0 & -5 \end{bmatrix}\)
- \(\begin{bmatrix} 5 & 0 \\ 0 & 5 \end{bmatrix}\)
- \(\begin{bmatrix} 0 & 5 \\ 5 & 0 \end{bmatrix}\)
- \(\begin{bmatrix} 0 & -5 \\ 5 & 0 \end{bmatrix}\)

**Correct Ans: D**

**Solution:**

Given,

\(A = \begin{bmatrix}0 & 5 \\-5 & 0 \end{bmatrix}\)

\(\Rightarrow\) Condition for Skew-symmetric matrix is \(A^T = -A\)

For matrix \(A =\begin{bmatrix}0 & 5 \\-5 & 0 \end{bmatrix}\)

\(\implies A^T = \begin{bmatrix}0 & -5 \\5 & 0 \end{bmatrix} = (-1) \begin{bmatrix}0 & 5 \\-5 & 0 \end{bmatrix} = -A \)

\(\therefore Skew-symmetric \: matrix

=\begin{bmatrix}0 & -5 \\5 & 0 \end{bmatrix}\)

- magnetic flux of magnetic circuit
- flux density of magnetic circuit
- permeability in magnetic circuit
- dipole moment of magnetic circuit

**Correct Ans: C**

**Solution:**

Reluctance \(S=\frac{l}{\mu A}\)

Where,

\(S\) - Reluctance in \(AT/Wb\)

\(l\) - Length of magnetic circuit in \(m\)

\(A\) - Area of cross-section of the magnetic path in \(m^2\)

\(\mu\) - Absolute permeability of the materials in \(H/m\)

\(S=\frac{l}{\mu A} \implies \mu=\frac{l}{S\times A}=\frac{m}{\frac{AT}{Wb}\times m^2}=\frac{Wb}{AT \times m}\)

- 2 Amps
- 8 Amps
- 5 Amps
- 4 Amps

**Correct Ans: C**

**Solution:**

\(\mathbf{Given \:data:}\)

An electric heater rating \(P=1\:kW=1000\:W,\:V=200\:V\)

\(P=\frac{V^2}{R}\implies R=\frac{V^2}{P}=\frac{(200)^2}{1000}=40\:\Omega\)

Current drawn by the heating element \(I=\frac{V}{R}=\frac{200}{40}=5\:A\)

- Separately excited DC generator
- Compound DC motor
- Separately excited DC motor
- Compound DC generator

**Correct Ans: A**

**Solution:**

\(\Rightarrow\) In given figure, the field winding is excited saperately by a DC source and so it is saperately excited DC machine.

\(\Rightarrow\) Here the current is flowing away from the armature and so it is generator.

- \( \frac{dy}{dx} = -4 \sin^3 x \)
- \( \frac{dy}{dx} = -4 \cos{x} \sin^3 x \)
- \( \frac{dy}{dx} = 4 \cos^3 x \)
- \( \frac{dy}{dx} = -4 \sin{x} \cos^3 x \)

**Correct Ans: D**

**Solution:**

- 12
- 11
- 10
- 13

**Correct Ans: A**

**Solution:**

\(\Rightarrow\) A ripple counter with \(n\) flipflops will able to count \(2^n-1\) counts.

\(\Rightarrow\) Here, the counter needs to count 3000. \(\quad \therefore 2^n-1 \geq 3000\).

\(\quad \therefore 2^n \geq 3001 \implies n = \frac{\log 3001}{\log 2} \approx 12.\)

- Fall in frequency
- Fall in voltage
- Fall in current
- Increase in current

**Correct Ans: C**

**Solution:**

Types of Shunt type of faults:

\(\rightarrow\) Line to Ground fault (L-G)

\(\rightarrow\) Line to Line fault (L-L)

\(\rightarrow\) Double Line to Ground fault (L-L-G)

\(\rightarrow\) Three phase fault

The shunt type faults characterized by:

\(\rightarrow\) Fall in voltage level

\(\rightarrow\) Fall in frequency

\(\rightarrow\) Increase in current value

Wire 1 and wire 2 are inductively linked. If their self-inductance is \(L_1\) and \(L_2\), mutual inductance is \(M\), then which of the following equations is the correct expression for \(E_1\)?

- \(E_1 = -L_1 \frac{di_1}{dt} - M\frac{di_2}{dt} \)
- \(E_1 = L_2 \frac{di_2}{dt} - M\frac{di_1}{dt} \)
- \(E_1 = -L_2 \frac{di_2}{dt} - M\frac{di_1}{dt} \)
- \(E_1 = L_1 \frac{di_1}{dt} - M\frac{di_2}{dt} \)

**Correct Ans: A**

**Solution:**

Self induced e.m.f. in coil 1 \(E_{S1}=-L_1\frac{dI_1}{dt}\)

Self induced e.m.f. in coil 2 \(E_{S2}=-L_2\frac{dI_2}{dt}\)

Mutually induced e.m.f. in coil 1 \(E_{m1}=-M\frac{dI_2}{dt}\)

Mutually induced e.m.f. in coil 1 \(E_{m2}=-M\frac{dI_1}{dt}\)

Total induced e.m.f. in coil 1 \(E_1=-L_1\frac{dI_1}{dt}-M\frac{dI_2}{dt}\)

\(\mathbf{Note:}\)

Total induced e.m.f. in coil 2 \(E_2=-L_2\frac{dI_2}{dt}-M\frac{dI_1}{dt}\)

Total induced e.m.f. in the combination \(E=E_{S1}+E_{S2}+E_{m1}+E_{m2}\)

- \( \frac{d^2y}{dx^2} = n^2 y \)
- \( \frac{d^2y}{dx^2} = -n^2 y \)
- \( \frac{d^2y}{dx^2} = n y \)
- \( \frac{d^2y}{dx^2} = -n y \)

**Correct Ans: B**

**Solution:**

\( y=a\cos{nx}+b\sin{nx}\)

\(\frac{dy}{dx} = [an ( -\sin nx) + b n \cos nx]\)

\(\frac{d^2y}{dx^2} = -an^2 \cos nx - bn^2 \sin nx\)

\(\frac{d^2y}{dx^2} = -n^2 [a \cos nx + b \sin nx]\)

\( \frac{d^2y}{dx^2} = -n^2 y \)

- 433.33 RPM
- 677.77 RPM
- 633.33 RPM
- 567.67 RPM

**Correct Ans: B**

**Solution:**

For the DC Shunt motor back emf is given by

\(E_b = V - I_aR_a \)

\(E_b = 500 - 60 \times 0.2 = 488 \: V\)

Back emf can also be written as

\(E_b = \frac{\phi Z N P}{60A} \)

For the wave winding number fo parallel paths \( A = 2 \)

So above equation can be written as

\(E_b = \frac{\phi Z N P}{60\times 2} \)

\(\implies\) \( N = \frac{E_b \times 60\times 2}{\phi Z P} \)

\(\implies\) \( N = \frac{488 \times 60\times 2}{0.03 \times 720 \times 4} \)

\(\implies\) \( N = 677.77 \: RPM \)

- RTD
- LVDT
- Strain gauge
- Piezoelectric transducer

**Correct Ans: C**

**Solution:**

The passive transducer converts change in non electrical quantity to a change in some passive electrical quantity, such as capacitance, resistance, or inductance.

Example: RTD, Strain Gauge

\(\Rightarrow\) Both RTD and strain gauge are resistive transducers but RTD is a temperature transducer and strain gauge is a pressure transducer.

- Geometric mean of
- ratio of
- difference between
- algebraic sum of

**Correct Ans: A**

**Solution:**

\(\mathbf{Series\:Resonance:}\)

\(\mathbf{Resonance\:Curve}\)

\(\Rightarrow\) Two points A and B on the resonance curve are known as half-power points.

\(\Rightarrow\) \(f_1\) - Lower cut-off frequency (Lower half-power frequency)

\(\Rightarrow\) \(f_2\) - Upper cut-off frequency (Upper half-power frequency)

\(\Rightarrow\) \(f_r\) - Resonance frequency is the Geometric mean of the two half power frequencies.

\(\Rightarrow\) Bandwidth (B.W) \(=f_2-f_1\)

\(\Rightarrow\) At below resonance frequency, Circuit behaves like a capacitive circuit \((X_C > X_L)\)

\(\Rightarrow\) At above resonance frequency, Circuit behaves like an inductive circuit \((X_L > X_C)\)

\(\Rightarrow\) At resonance frequency, Circuit behaves like a purely resistive circuit \((X_L = X_C)\)

The above one line diagram represents:

- Equivalent circuit of induction motor
- Equivalent circuit of filter
- Equivalent circuit of synchronous motor
- Equivalent circuit of generator

**Correct Ans: D**

**Solution:**

\(\Rightarrow\) Given single line diagram is equivalent circuit of generator because here current flows outwards, it is also a synchronous machine because it contains synchronizing reactance \( jX_s \).

- \(H(j \omega) = \frac{j \omega RC}{1+RC j \omega}\)
- \(H(j \omega) = \frac{j \omega }{1+RC j \omega}\)
- \(H(j \omega) = \frac{RC }{1+RC j \omega}\)
- \(H(j \omega) = \frac{j \omega RC}{RC + j \omega}\)

**Correct Ans: A**

**Solution:**

\(\Rightarrow \)For Simple RC High Pass Filter, the circuit will be:

\(\Rightarrow\) As per voltage-divider relationship,

\(V_{out} = \frac{R}{R-jX_c}\:V_{in}\)

\(\implies \) Transfer Function \(=H(j\omega) =\frac{V_{out}}{V_{in}}= \frac{R}{R-jX_c}\)

\(\quad \quad = \frac{R}{R+\frac{1}{j\omega C}}\)

\(\quad \quad = \frac{j\omega RC}{1+j\omega RC}\)

- They are equal in magnitude and displayed from each other by \(60^o\) with the same sequence as the original phases
- They are unequal in magnitude and displayed from each other by \(120^o\) with the same sequence as the original phases
- They are equal in magnitude and displayed from each other by \(120^o\) with the same sequence as the original phases
- They are unequal in magnitude and displayed from each other by \(60^o\) with the same sequence as the original phases

**Correct Ans: C**

**Solution:**

- \(G(s)=\frac{C(s)}{R(s)} = \frac{\sum_{k=1}^n P_k\Delta}{2\Delta_k} \)
- \(G(s)=\frac{C(s)}{R(s)} = \frac{\sum_{k=1}^n P_k\Delta}{\Delta_k} \)
- \(G(s)=\frac{C(s)}{R(s)} = \frac{\sum_{k=1}^n P_k\Delta_k}{2\Delta} \)
- \(G(s)=\frac{C(s)}{R(s)} = \frac{\sum_{k=1}^n P_k\Delta_k}{\Delta} \)

**Correct Ans: D**

**Solution:**

\(\Rightarrow \mathbf{Mason's\: Gain\: Formula:}\) The relation between an input variable and an output variable of a Signal Flow Graph is given by Mason's Gain Formula.

\(\implies\) The overall system gain is given by:

\(G(s)=\frac{C(s)}{R(s)} = \frac{\sum_{k=1}^n P_k\Delta_k}{\Delta} \)

where,

\(\rightarrow P_k =\) Forward path gain of the \(K^{th}\) forward path.

\(\rightarrow \Delta = 1 - \) [Sum of the loop gain of all individual loops] + [Sum of gain products of all possible two non-touching loops] + [Sum of gain products of all possible three non-touching loops] + .......

\(\rightarrow \Delta_k \) is obtained from \(\Delta\) by removing the loops which are touching the kth forward path.

- SCR
- TRIAC
- DIAC
- PUT

**Correct Ans: B**

**Solution:**

\(\Rightarrow\) The symbol shown in figure is of TRIAC.

\(\Rightarrow\) TRIAC is a controlled bidirectional switch.

- \( \Big ( \frac{dE^x}{dx} + \frac{dE^y}{dy}+\frac{dE^z}{dz}\Big)=\frac{3\rho}{\varepsilon_0}\)
- \( \Big ( \frac{dE^x}{dx} + \frac{dE^y}{dy}+\frac{dE^z}{dz}\Big)=\frac{\sqrt[3]{\rho}}{\varepsilon_0}\)
- \( \Big ( \frac{dE^x}{dx} + \frac{dE^y}{dy}+\frac{dE^z}{dz}\Big)=\frac{2\rho}{\varepsilon_0}\)
- \( \Big ( \frac{dE^x}{dx} + \frac{dE^y}{dy}+\frac{dE^z}{dz}\Big)=\frac{\rho}{\varepsilon_0}\)

**Correct Ans: D**

**Solution:**

\(\Rightarrow\) Differential form of Gauss law states that the divergence of electric field E at any point in space is equal to \(\frac{1}{\varepsilon_0}\) times the volume charge density, \( \rho \), at that point.

\( \Big ( \frac{dE^x}{dx} + \frac{dE^y}{dy}+\frac{dE^z}{dz}\Big)=\frac{\rho}{\varepsilon_0}\)

\(\frac{dy}{dx}=\sqrt{\frac{1-y^2}{1-x^2}} \)

- \(\cos y = \cos x + c \)
- \(\sin^{-1} y = \sin^{-1} x + c \)
- \(\cos^{-1} y = \cos^{-1} x + c \)
- \(\sin y = \sin x + c \)

**Correct Ans: B**

**Solution:**

Given,

\(\frac{dy}{dx}=\sqrt{\frac{1-y^2}{1-x^2}} \)

\(\Rightarrow\) \(\sqrt{1-x^2} \: dy = \sqrt{1-y^2} \: dx\)

\(\Rightarrow\) \(\frac{dy}{\sqrt{1-y^2}} = \frac{dx}{\sqrt{1-x^2}} \)

Apply Integration both side,

\(\Rightarrow\) \(\int \frac{dy}{\sqrt{1-y^2}} = \int \frac{dx}{\sqrt{1-x^2}} \)

\(\implies \sin^{-1} y = \sin^{-1} x + C\)

Above symbol represents:

- OR-AND Invert Gate
- AND-OR Invert Gate
- Schmitt Gate
- Inhibit Logic Gate

**Correct Ans: A**

**Solution:**

\(\Rightarrow\) The OAI (OR AND Invert) gate is used to realize the product of sum form of Boolean function.

\(\Rightarrow\) It is used in CMOS technology.

\(\Rightarrow\) It reduces the number of transistor needed to implement a Boolean function.

- \(K=2\pi f \sqrt{ \varepsilon_r \mu_r} \)
- \(K=2\pi f \sqrt{ \varepsilon_r \varepsilon_0 \mu_r \mu_0} \)
- \(K=2\pi f \sqrt{ \varepsilon_0 \mu_0} \)
- \(K=\pi f \sqrt{ \varepsilon_r \varepsilon_0 \mu_r \mu_0} \)

**Correct Ans: B**

**Solution:**

\(\Rightarrow\) Wave number \((k)\), when the wave is traveling through any material other than the vacuum is given by:

\(K=2\pi f \sqrt{ \varepsilon_r \varepsilon_0 \mu_r \mu_0} \)

- \(2^{nd}\:quadrant\)
- \(1^{st}\:quadrant\)
- \(1^{st} \: and \: 2^{nd}\:quadrants\)
- \(1^{st} \: and \: 4^{th}\:quadrants\)

**Correct Ans: A**

**Solution:**

\(\Rightarrow\) Type A chopper \(\rightarrow\) First quadrant operation (+ve voltage and +ve current)

\(\Rightarrow\) Type B chopper \(\rightarrow\) Second quadrant operation (+ve voltage and -ve current)

\(\Rightarrow\) Type C chopper \(\rightarrow\) First and second quadrant operation (+ve voltage and current in both direction)

\(\Rightarrow\) Type D chopper \(\rightarrow\) First and fourth quadrant operation (-ve and +ve voltage and +ve current)

\(\Rightarrow\) Type E chopper \(\rightarrow\) Four quadrant operation

- 6
- 4
- 5
- 3

**Correct Ans: C**

**Solution:**

\(\Rightarrow \mathbf{Forward\: paths\: for\: given\: SFG:}\) From R(s) to C(s)

\(\implies 1.\quad G_1 \rightarrow G_2 \)

\(\implies 2.\quad G_7 \rightarrow G_8 \)

\(\implies 3.\quad G_4\)

\(\implies 4.\quad G_7 \rightarrow G_6 \rightarrow G_2\)

\(\implies 5.\quad G_1 \rightarrow G_5 \rightarrow G_8\)

- The magnetic field intensity must be tangential or normal to the path.
- The path is called Amperian path.
- The law does not depend on the shape of the path.
- The path need not to enclose the direct current.

**Correct Ans: D**

**Solution:**

\(\Rightarrow\) Ampere's circuital law states that the integral of magnetic field density (B) along an imaginary closed path is equal to the product of current enclosed by the path and permeability of the medium.

\(\Rightarrow\) So this law is applicable for the closed path only.

- To provide an additional voltage gain
- To bring the DC voltage level to 0 volts with respect to ground
- To increase the output voltage swing
- To provide most of the voltage gain

**Correct Ans: B**

**Solution:**

- Thermistor
- Thermocouple
- Photo voltaic transducer
- Piezoelectric transducer

**Correct Ans: A**

**Solution:**

\(\Rightarrow\) The passive transducer converts change in non electrical quantity to a change in some passive electrical quantity, such as capacitance, resistance, or inductance.

Example: RTD, Strain Gauge, Thermistor

\(\Rightarrow\) The active transducer converts change in non electrical quantity to a change in some active electrical quantity, such as current or voltage without any auxilary power supply.

Example: Thermocouple, Photo voltaic transducer, Piezoelectric transducer

- \(dV = \frac{\partial V}{\partial x} dz+ \frac{\partial V}{\partial y} dx+ \frac{\partial V}{\partial z} dy\)
- \(dV = \frac{\partial V}{\partial x} dx+ \frac{\partial V}{\partial y} dz+ \frac{\partial V}{\partial z} dy\)
- \(dV = \frac{\partial V}{\partial x} dy+ \frac{\partial V}{\partial y} dz+ \frac{\partial V}{\partial z} dx\)
- \(dV = \frac{\partial V}{\partial x} dx+ \frac{\partial V}{\partial y} dy+ \frac{\partial V}{\partial z} dz\)

**Correct Ans: D**

**Solution:**

\(\Rightarrow\) If V is the electric potential in an electromagnetic field, then find the notation of \(dV\) is given by

\(dV = \frac{\partial V}{\partial x} dx+ \frac{\partial V}{\partial y} dy+ \frac{\partial V}{\partial z} dz\)

- \(1\:k\Omega\)
- \(990\:\Omega\)
- \(9.9\: k\Omega\)
- \(10\: k\Omega\)

**Correct Ans: C**

**Solution:**

\(\Rightarrow\) To measure \(0-100\:V\) by \(100\: \Omega\) instrument having full scale at \(10\: mA\) suppose resistance R is connected in series with the instrument.

\(\Rightarrow\) If \(0 \: V \) is applied across the combination \( 0 \: A\) flows through it and so displacement will be zero.

\(\Rightarrow\) If \( 100 \: V \) is applied across the combination \(10\: mA\) should flow through it.

So \( 10\: mA = \frac{100 \: V}{R + R_i} \)

\(\Rightarrow\) \( 10\: mA = \frac{100 \: V}{R + 100} \)

\(\Rightarrow\) \( R + 100 = \frac{100 \: V}{10\: mA} = 10000 \)

\(\Rightarrow\) \( R = 9.9 \: k\Omega \)

\(\Big (I_a = \) Armature Current, \(I_L=\) Load Current, \(I_{se}=\) Series Field Current and \(I_{sh}=\) Shunt Field Current\(\Big )\)

- \(I_{se}= I_a+I_{sh} \)
- \(I_{se}= I_a+I_{L} \)
- \(I_{se}= I_a+I_{sh}+I_L \)
- \(I_{se}= I_L \)

**Correct Ans: D**

**Solution:**

Equivalent electrical circuit of short shunt compound wound generator is given by

From above circuit it is clear that the series current of short shunt compound generator is equal to load current.

- \(t < t_0\)
- \(t_0 \geq t \geq t_1 \)
- \(t_0 > t_1\)
- \(t < t_1\)

**Correct Ans: B**

**Solution:**

\(\Rightarrow\) A system is said to be \(\mathbf{Controllable}\), if it is possible to transfer the system state from any initial state to any desired state in finite interval of time.

\(\Rightarrow\) A system is said to be \(\mathbf{Observable}\), if every state can be completely identified by measurements of the outputs at the finite time interval.

\(\Rightarrow\) For given options, only option B indicated finite time interval.