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Year 2024
April
Week # 1
Expire on 30 Apr 2024
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FAQs
April
Week # 2 Quiz 1
Q1.
The four no-load speeds of three-phase induction motors operating on 400 V, 50 Hz supply are 576 rpm, 720 rpm, 1440 rpm, and 2880 rpm. The number of poles of the motor, respectively, are
12, 8, 4, 2
8, 6, 4, 2
16, 8, 4, 2
10, 8, 4, 2
Q2.
A single phase transformer when supplied from a 220V, 50Hz supply has eddy current loss of 50 W. If the transformer is connected to a voltage of 330 V, 50 Hz, the Eddy current loss will be
168. 75 w
112. 5 w
75 w
50 W
Q3.
A three phase, 10 kW, 4-pole, 50 Hz induction motor has full load speed of 1440 rpm. The friction and windage loss of the motor at this speed is 500 W. Calculate the rotor copper loss.
295 W
395 W
327.5 W
437.5 W
Q4.
A 200/400 V, 20 kVA, 2-winding transformer is connected as an auto-transformer to transform 600 V to 200 V. Calculate the KVA rating of the auto-transformer.
30 kVA
25 kVA
60 kVA
50 kVA
Q5.
A 10-pole induction motor is supplied by a 6-pole alternator, which is driven at 1400 rpm. If the motor runs with a slip of 5%, what is its speed?
1575 rpm
882 rpm
1425 rpm
798 rpm
Q6.
The frequency of the supply to the stator of an 8-pole induction motor is 50Hz and the rotor frequency is 3Hz. The slip is_________.
0
0.02
0.04
0.06
Q7.
A \(\frac{2200}{1100}\)V, 50 Hz single-phase transformer having a negligible winding resistance operates from a variable voltage, variable frequency supply such that \(\frac{V}{f}\)is constant. Which of the following options is correct about the range of frequencies?
hysteresis loss vary and constant eddy current loss
no variation either in eddy current or hysteresis loss
eddy current loss vary and constant hysteresis loss
both hysteresis loss and eddy current loss varies
Q8.
A shunt generator delivers 195 A at a terminal p. d. of 250 V. The armature resistance and shunt field resistance are 0.02 Ω and 50 Ω respectively. The value of generated EMF is .
282
270
246
254
Q9.
A DC shunt motor takes 5A at 100V when running light. Shunt field resistance is 50 ohm and armature resistance is 0.2 ohm. What will be driving power?
204 W
298 W
412 W
305 W
Q10.
If 'Pm' is the gross mechanical power developed, 'Pcu' is the rotor copper loss and 's' is the slip of induction motor, then the ratio of rotor copper loss to the gross mechanical power developed is ________ .
\(\frac{P_{cu}}{P_m}=s\)
\(\frac{P_{cu}}{P_m}=1-s\)
\(\frac{P_{cu}}{P_m}=\frac{1-s}{s}\)
\(\frac{P_{cu}}{P_m}=\frac{s}{1-s}\)
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