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MCQ
BASIC ELECTRONICS
CONTROL SYSTEM ENGINEERING
DIGITAL ELECTRONICS
ELECTRICAL CIRCUIT ANALYSIS
ELECTRICAL ENERGY CONSERVATION AND AUDITING
ELECTRICAL ENGINEERING MATERIALS
ELECTRICAL MACHINES
ELECTRICAL VEHICLES
ELECTRICAL WIRING
ELECTROMAGNETICS
MEASUREMENT & INSTRUMENTATION
MICROPROCESSOR AND MICROCONTROLLER INTERFACING
POWER ELECTRONICS & DRIVES
POWER SYSTEM
SIGNALS & SYSTEMS
UTILIZATION OF ELECTRICAL ENERGY
ELECTRICAL CIRCUIT ANALYSIS
Q1.
The hot resistance of filament of bulb is higher than cold resistance of filament lamp because of temperature coefficient of filament is
negative
zero
infinite
positive
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Solution
Q2.
In practice, earth is chosen as a place of zero electric potential because it
is non conducting
is easily available
keeps losing and gaining electric charge every moment
has almost constant potential
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Solution
Q3.
How many coulombs of charge flow through a circuit carrying a current of 10 A in 1 minute?
10
60
600
1200
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Solution
Q4.
E.M.F can be induced in a circuit by___________________.
Changing magnetic flux density
Changing area of circuit
Changing the angle
All of above
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Solution
Q5.
If the diameter of the wire is halved its current carrying capacity become about.
one fourth
half
twice
four times
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Solution
Q6.
The electrical conductivity of metals is typically of the order of (in \(ohm^{-1}\)\(m^{-1}\))
\(10^7\)
\(10^5\)
\(10^{-4}\)
\(10^{-6}\)
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Solution
Q7.
An electrical lamp consumes 100 W of power. If the supply voltage is 220 V the energy consumed in 30 minutes is
0.005 kWh
0.05 kWh
0.5 kWh
5 kWh
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Solution
Q8.
Which of the following is the poorest conductor of electricity ?
copper
silver
carbon
aluminium
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Solution
Q9.
4 resistors of equal value, when connected in series across 250 V supply, dissipate power 25 Watt. If same resistors are connected in parallel, the power dissipation will be
25 Watt
100 Watt
200 Watt
400 Watt
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Solution
Q10.
A 50 W electric light bulb is connected to a 200 V supply. Determine (a) the current flowing in the bulb and (b) the resistance of the bulb.
0.5 A and 400 \(\Omega\)
0.25 A and 800 \(\Omega\)
0.5 A and 800 \(\Omega\)
0.25 A and 400 \(\Omega\)
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Solution
1
2
3
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